Use the graph below what is the average rate of change from x=2 to x=3

9) Two ships follow the parallel paths shown on the map.

Monica [59]

Answer:

The nautical mile is based on the Earth's longitude and latitude coordinates, with one nautical mile equaling one minute of latitude.

Step-by-step explanation:

3 0

2 years ago

I've been stuck on this for about 2 hours but it still doesn't make any sense to me, please helpppppppppp

Mariana [72]

I really hope this helps. I’m sure the answer is c:)

5 0

3 years ago

For brainiest:):):):):)

guajiro [1.7K]

Answer:

number one is 22 number two is 16 number three is 32

Step-by-step explanation:

4 0

3 years ago

Kyle received the following course grades for 10 (three-credit) courses during his freshman year:

timofeeve [1]

Answer:

(a) The average grade point is 2.5.

(b) The relative frequency table is show below.

(c) The mean of the relative frequency distribution is 0.3333.

Step-by-step explanation:

The given data set is

4, 4, 4, 3, 3, 3, 1, 1, 1, 1

(a)

The average grade point is

$Average=\frac{\sum x}{n}$

$Average=\frac{4+4+4+3+3+3+1+1+1+1}{10}$

$Average=2.5$

Therefore the average grade point is 2.5.

(b)

$\text{Relative frequency}=\frac{\text{Frequency of number}}{\text{Total frequency}}$

The relative frequency table is show below:

x f Relative frequency

4 3 $\frac{3}{10}=0.3$

3 3 $\frac{3}{10}=0.3$

1 4 $\frac{4}{10}=0.4$

(c)

Mean of the relative frequency distribution is

$Average=\frac{0.3+0.3+0.4}{3}$

$Average=0.3333$

Therefore the mean of the relative frequency distribution is 0.3333.

4 0

3 years ago

A man hits a baseball when it is 4 ft above the ground with an initial velocity of 120 ft/sec. The ball leaves the bat at a 30 d

Sauron [17]

<span>et us assume that the origin is the floor right below the 30 ft. fence

To work this one out, we'll start with acceleration and integrate our way up to position.

At the time that the player hits the ball, the only force in action is gravity where: a = g (vector)
ax = 0
ay = -g (let's assume that g = 32.8 ft/s^2. If you use a different value for gravity, change the numbers.

To get the velocity of the ball, we integrate the acceleration
vx = v0x = v0cos30 = 103.92
vy = -gt + v0y = -32.8t + v0sin40 = -32.8t + 60

To get the positioning, we integrate the speed.
x = v0cos30t + x0 = 103.92t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + 60t + 4

If the ball clears the fence, it means x = 0, y > 30

x = 0 -> 103.92 t - 350 = 0 -> t = 3.36 seconds

for t = 3.36s,
y = -16.4(3.36)^2 + 60*(3.36) + 4
= 20.45 ft

which is less than 30ft, so it means that the ball will NOT clear the fence.

Just for fun, let's check what the speed should have been :)

x = v0cos30t + x0 = v0cos30t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + v0sin30t + 4

x = 0 -> v0t = 350/cos30
y = 30 ->
-16.4t^2 + v0t(sin30) + 4 = 30
-16.4t^2 + 350sin30/cos30 = 26
t^2 = (26 - 350tan30)/-16.4
t = 3.2s

v0t = 350/cos30 -> v0 = 350/tcos30 = 123.34 ft/s

So he needed to hit the ball at at least 123.34 ft/s to clear the fence.

You're welcome, Thanks please :)
</span>

6 0

3 years ago