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2 years ago

Add the following polynomials, then write the answer in descending powers of x

Mathematics

1 answer:

Margarita [4]2 years ago

8 0

Answer:

5x^3-4x-1

Step-by-step explanation:

https://www.symbolab.com/solver/step-by-step/2x%5E%7B3%7D%2B4x-6%20%2B%203x%5E%7B3%7D-8x%2B7

I use symbolab, it's the best calculator for everything. Hope this helps!

You might be interested in

To which interval would we restrict f(x) = cos (x-π/4) so that f(x) is invertible?

nadezda [96]

Answer:

The range of x values for which y is unique is 2·π

Step-by-step explanation:

For a function j: X → Y to be invertible, we have that for every y in Y, there is associated only one x which is an element of x

Hence, f(x) = cos(x - π/4) gives

the x intercept at two penultimate points of the graph of cos(x - π/4) are;

x = 2.36, and x = 8.64

x = 3/4·π, and x = 2.75·π = $2\tfrac{3}{4}\cdot \pi$

Hence the range of x values for which y is unique is presented as follows

$2\tfrac{3}{4}\cdot \pi - \frac{3}{4}\cdot \pi = 2}\cdot \pi$

The range of x values for which y is unique = 2·π.

4 0

2 years ago

The triangular numbers are defined by the recursive formula t1 = 1, tn = tn - 1 + n, where n ∈N and n > 1. What are the first

GalinKa [24]

ANSWER

C) 1, 3, 6, 10, 15, 21, 28, 36, 45

EXPLANATION

The recursive formula is,

$t_1=1,t_n=t_{n-1}+n$

when n is a natural number greater than 1.

When n=2,

$t_2=t_{2-1}+2$

$t_2=t_{1}+2 = 1 + 2 = 3$

when n=3,

$t_3=t_{2}+2 = 3 + 3= 6$

when t=4,

$t_4=t_{3}+2 = 6+ 4= 10$

When t=5,

$t_5=t_{4}+5 = 10 + 5 = 15$

when t=6,.

$t_6=t_{5}+6 = 15 + 6 = 21$

when t=7

$t_7=t_{6}+7 = 21 + 7 = 28$

When t=8,

$t_8=t_{7}+8 = 28 + 8 = 36$

When t=9,

$t_9=t_{8}+9 = 36 + 9 = 45$

Hence the first nine triangular number are

C) 1, 3, 6, 10, 15, 21, 28, 36, 45

3 0

3 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So $\mu = 373, \sigma = 67$

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So $n = 5, s = \frac{67}{\sqrt{5}} = 29.96$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 373}{29.96}$

$Z = 1.23$

$Z = 1.23$ has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So $\mu = 526, \sigma = 107$