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3 years ago

Beyonce went to the mall and saw a

Mathematics

1 answer:

svetoff [14.1K]3 years ago

4 0

The answer is $9,100

6,500 x .08 = 520
520 x 5 = 2,600
2,600 + 6,500 = 9,100

Hope this helps!

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To the nearest tenth of a degree, ﬁnd the sizes of the acute angles in the 7-24-25 right

fiasKO [112]

First of all, just to avoid being snookered by a trick question, we should verify that these are really right triangles:

7² + 24² really is 25² , and 8² + 15² really is 17² , so we're OK there.

In the first one:
sin(one acute angle) = 7/25 = 0.28
the angle = sin⁻¹ (0.28) = 16.26°
the other acute angle = (90° - 16.26°) = 73.74°

In the second one:
sin(one acute angle) = 8/17 = 0.4706...
the angle = sin⁻¹ (0.4706...) = 28.07°
the other acute angle = (90° - 28.07°) = 61.93°

I'm sorry, but just now, I don't know how to do the
third triangle in the question.

7 0

4 years ago

Which of the following is the solution to the differentiable equation dy/dx=4x/y, where Y(2)=-2

aliya0001 [1]

First we'll substitute $\frac{dy}{dx}$ with $y'$

$y'=\frac{4x}{y}$

Then we can separate this.

$yy'=4x$

Then we'll solve this.

$yy'=4x: \frac{y^2}{2}=2x^2+c_1$

$\frac{y^2}{2}=2x^2-6$

$y=2\sqrt{x^2-3},y=-2\sqrt{x^2-3}$

Then we'll plug in to find the extraneous solutions (if any)

$y=-2\sqrt{x^2-3}$

7 0

3 years ago

How to know if the number is a perfect square

emmasim [6.3K]

Answer:

Step-by-step explanation:

Prime factorize the given number. All factors should have pair. If all factors have pair, then it is a perfect square

EG: 36 : Factors of 36 are 2,3,2,3. Here there are two 2's and two 3's. so 36 is a perfect square.

EG: 24: Factors of 12 are 2,2,3. Here 3 is without pair. so it is not a perfect square.

3 0

3 years ago

A video game store has an 30% sale on all video games . If the game you want cost $45.00 , what would the discount be ?

Zina [86]

Answer:

31.5

Step-by-step explanation:

.......

8 0

3 years ago

The data shown represent the number of runs made each year during Bill Mazeroski’s career. Check for normality.

const2013 [10]

Answer:

The given data is not normal.

Step-by-step explanation:

We are given the following data:

30, 59, 69, 50, 58, 71, 55, 43, 3, 66, 52, 56, 62, 36, 13, 29, 17, 31

Condition for normality:

Mean = Mode = Median

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{800}{18} = 44.44$

Mode is the most frequent observation of the data.

Since all the value appeared once, there is no mode.

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

Sorted data: 3, 13, 17, 29, 30, 31, 36, 43, 50, 52, 55, 56, 58, 59, 62, 66, 69, 71

Median =

$=\dfrac{9^{th}+10^{th}}{2} = \dfrac{50+52}{2}=51$

Since the mean, mode and median of data are not equal, the data is not normal.

7 0

3 years ago