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Anit [1.1K]
4 years ago
7

Find the inverse of f(x)=(x-1)^3

Mathematics
1 answer:
Shtirlitz [24]4 years ago
7 0
f (x)=(x-1)^3 \\ y =(x-1)^3 \\\\\sf Replace~ x ~with~ y ~and~ vice~ versa   \\ x = (y-1)^3 \\  \sqrt[3]{x} =y-1 \\ \\  Solve~for~y\\\\ \boxed {y= \sqrt[3]{x} +1}
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The value of the expression 2\cos(t) + \tan^2(t) is 4 and the exact value of \sin^{-1}(\sin(\frac{5\pi}{3})) is \frac{5\pi}{3}

<h3>How to determine the trigonometry expression?</h3>

The point on the unit circle is given as:

P = (\frac 12, \frac{\sqrt{3}}2)

A point on a unit circle is represented as: (x,y), such that:

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<h3>How to solve the arcsin expression?</h3>

The expression is given as:

\sin^{-1}(\sin(\frac{5\pi}{3}))

As a general rule, the arc sine of sine x is x.

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\sin^{-1}(\sin(\frac{5\pi}{3})) = \frac{5\pi}{3}

Hence, the exact value of \sin^{-1}(\sin(\frac{5\pi}{3})) is \frac{5\pi}{3}

Read more about trigonometry expressions at:

brainly.com/question/8120556

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