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valina [46]
3 years ago
14

What is the LCM of 168 and 196.

Mathematics
2 answers:
romanna [79]3 years ago
7 0

Answer:

1176

hope this will help you

vaieri [72.5K]3 years ago
7 0

Answer:

Step-by-step explanation:

2L168      

2L84

2L42

3L21

7L7

2x2x2x3x7=168

2L196

2L98

7L49

7L7

2x2x7x7=196

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7 0
3 years ago
Which function represents a vertical stretch of an exponential function?
nika2105 [10]

Answer:

A. f(x)=3(\frac{1}{2})^x

Step-by-step explanation:

The options are:

A. f(x)=3(\frac{1}{2})^x\\\\B. f(x)=\frac{1}{2}(3)^x\\\\C. f(x)=(3)^{2x}\\\\ D. f(x)=3^{(\frac{1}{2}x)}

For this exercise it is important to remember that, by definition, the Exponential parent functions have the form shown below:

f(x) = a^x

Where "a" is the base.

There are several transformations for a function f(x), some of those transformations are shown below:

1. If  bf(x) and  b>1, then the function is stretched vertically by a factor of "b".

2. If   bf(x)  and 0, then the function is  compressed vertically by a factor of "b"

Therefore, based on the information given above, you can identify that the function that represents a vertical stretch of an Exponential function, is the one given in the Option A. This is:

f(x)=3(\frac{1}{2})^x

Where the factor is:

b=3

And 3>1

7 0
3 years ago
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Factor the following expression. Simplify your answer.<br> 3s(s - 1)^1/3 + 2(s - 1)^4/3
denis23 [38]

Answer:

Step-by-step explanation:

3s\sqrt[3]{s-1} + 2 \sqrt[4/3]{s-1} =\\3s\sqrt[3]{s-1} + 2 \sqrt[1/3]{(s-1)^4} =\\3s\sqrt[3]{s-1} + 2 (s-1)\sqrt[1/3]{s-1} =\\\sqrt[3]{s-1}*(3s + 2 (s-1)) =\\\sqrt[3]{s-1}*(3s + 2s-2)) =\\\sqrt[3]{s-1}*(5s -2) \\

6 0
2 years ago
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Assume lim f(x)-6 and lim g(x)-9. Compute the following limit and state the limit laws used to justify the computation.
emmasim [6.3K]

Answer:

4

Step-by-step explanation:

<h3><u>some relevant limit laws</u></h3>

lim C = C where c is a constant.

lim( f(x)  + g(x)) =lim f(x) + lim g(x)

lim( f(x)g(x)) =lim f(x) * lim g(x)

lim( cg(x)) =clim g(x)

lim( f(x)/g(x)) =lim f(x) / lim g(x) if  lim g(x) is not equal to zero.

lim( f(x))^2 = (lim f(x) )^2

lim  square root( f(x)) = square root(lim f(x) )

\lim_{n \to 3} g(x)  = 9\\\\\lim_{n \to 3} f(x)  = 6\\\\ \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10} \\\\ = \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10}\\\\= \sqrt[3]{lim_{n \to 3}f(x) \times lim_{n \to 3}g(x) + 10}\\\\= \sqrt[3]{6 \times 9 + 10}\\\\= \sqrt[3]{64}

= 4

4 0
4 years ago
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