The expression is:
(z^2 - 4)
_______
z - 3
_______________
z + 2
___________
z^2 + z - 12
You can factor the numerator z^2 - 4 = (z + 2) (z - 2)
And the denominatior z^2 + z + 12 = (z + 4)(z - 3)
That permits to write the quotient as:
(z + 2)(z - 2)
___________
z - 3
_______________
z + 2
___________
(z + 4)(z - 3)
Now you can multiplicate the numerator of the numerator times the denominator of the denominator, and multtiplicate the denominator of the numerator times the numerator of the denominator to obtain:
(z + 2)(z - 2)(z + 4)(z - 3)
____________________
(z - 3)((z + 2)
Cancel the factors (z - 3) and (z + 2) because they are in both the numerator and the denominator =>
(z - 2)(z + 4) = z^2 + 2z - 8
The restrictions are that none of the cancelled factors can be 0, so z ≠ 3 and z ≠- 4.
Answer:
could be on 3/6 or 4/8
Step-by-step explanation:
Answer:
7x² + x – 2
Step-by-step explanation:
(4x² + 3) – (–3x² – x + 5)
First, distribute the minus sign to eliminate the parentheses (negative terms become positive and vice versa):
4x² + 3 + 3x² + x – 5
Then, combine like terms:
7x² + x – 2
I would have to say the answer is=<span>C) 16x3 - 8x2y - 16xy2 - 64y3</span>