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Marysya12 [62]
4 years ago
8

The play director spent 190190190190 hours preparing for a play. That time included attending 35353535 rehearsals that took vary

ing amounts of time and spending 933493 \dfrac{3}{4}9343​93, start fraction, 3, divided by, 4, end fraction hours on other responsibilities related to the play. What question does the equation 35x+9334=19035x+93\dfrac{3}{4}=19035x+9343​=19035, x, plus, 93, start fraction, 3, divided by, 4, end fraction, equals, 190 help answer?
Mathematics
1 answer:
Genrish500 [490]4 years ago
7 0

Answer:

The equation above represents the total time the play director spent preparing for a play.

Step-by-step explanation:

The time spent by the play director for preparing for a play is, 190 hours.

Of these 190 hours, the director spent varying amounts of time attending 35 rehearsals for the play.

Let the varying amounts of time be denoted by, <em>x</em>.

The director also spent 3/4th of an hour, i.e. 45 minutes, on other responsibilities related to the play.

The equation provided is:

35x+\frac{3}{4}=190

The equation above represents the total time the play director spent preparing for a play.

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Step-by-step explanation:

For uniform distribution between a & b

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For 110 and 150,

Mean, xbar = (150 + 110)/2 = 130

Standard deviation, σ = √((150-110)²/12 = 11.55

To find the probability that x will take on a value between 120 and 125

We need to standardize 120 & 125

z = (x - xbar)/σ = (120 - 130)/11.55 = - 0.87

z = (x - xbar)/σ = (125 - 130)/11.55 = - 0.43

P(120 < x < 125) = P(-0.87 < x < -0.43)

We'll use data from the normal probability table for these probabilities

P(120 < x < 125) = P(-0.87 < x < -0.43) = P(z ≤ -0.43) - P(z ≤ -0.86) = 0.33360 - 0.19215 = 0.14145

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3 years ago
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3 years ago
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Answer:

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Step-by-step explanation:

We are given the following information in the question:

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