Answer:
36years
Step-by-step explanation:
Let charity present age be x
Charity daughter present age be y
Charity husband present age be z
If the sum of their ages ten years to come is 117, then;
10+x+10+y+10+z = 117
30+x+y+z = 117
x+y+z = 87 ... 1
If charity is four times as old as her daughter, then;
x = 4y
y = x/4 ... 2
If she is also six years younger than her husband, then;
x = z- 6
z = x+6 .. 3
Substitute 2 and 3 into 1;
x + x/4 + (x+6) = 87
Multiply through by 4
4x + x + 4(x+6) = 4(87)
5x+4x+24 = 348
9x = 348 - 24
9x = 324
x = 324/9
x = 36
hence Charity is 36years old today
In algebraic terms this is:
The integer is 2.
Answer:
If y(x-y)^2=x, then int1/(x-3y)dx is equal to (A) 1/3log{(x-y)^2+1} (B) 1/4log{(x-y)^2-1} (C) 1/2log{(x-y)^2-1} (D) 1/6 log{(x^2-y^2-1}
Step-by-step explanation:
Answer:
3384
Step-by-step explanation:
Answer:
4.5
Step-by-step explanation:
First we need to turn the ratio of 1 : 3 into a fraction
1:3 = 1/3
Next we need to square that fraction
1 x 1 = 1
3 x 3 = 9
Then we turn those numbers into a fraction
1/9
We turn the .5 into a fraction
.5/x
And cross multiply both fraction by each other
1/9 x .5/x
1 x X = X
9 x .5 = 4.5
So
4.5 = X
