Question

The Attachment below is the question

Answer 1

A normal die is six sided.

The probability of rolling a 5 is 1/6

The probability of rolling a factor of 6 is 4/6 (or 2/3)
-the factors of 6 are 1, 2, 3 and 6

The probability of rolling a number more than one is 5/6
-the die is numbered 1-6, and the numbers greater than one are 2, 3, 4, 5 and 6

If you’re rolling the die 3 times and want to get those three in that specific order:

Multiply 6 x 3 to get 18
-you roll a six sided die 3 times

The probability of rolling a 5 the first time is 1/18

The probability of rolling a factor of 6 the second time is 4/18 (or 2/9)
-(see factors of 6 above)

The probability of rolling a number greater than 1 is 5/18

Next multiply 18 x 3, which is equal to 54
-this is because you want to find the EXACT theoretical probability of rolling these numbers in this exact order

Add up all your numerators
1 + 4 + 5 = 10

Your probability of rolling these numbers in this exact order is 10/54.

But you must ALWAYS simplify your fractions.

Simplify 10/54:
10 / 2 = 5
54 / 2 = 27

Your simplified fraction is 5/27.

Hope this helped! :3