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AveGali [126]
3 years ago
12

What number needs to be added to 5 and 3 so that the ratio of the first number to the second becomes 3:2?

Mathematics
2 answers:
sukhopar [10]3 years ago
7 0

Answer:

7

Step-by-step explanation:

x + 3 : x + 8 : : 2 : 3

(x + 3) \times 3 = (x + 8) \times 2 \\ 3x + 9 = 2x + 16 \\ 3x - 2x = 16 - 9 \\ x = 7 \\ x + 3 = 7 + 3 = 10 \\ x + 8 = 7 + 8 = 15 \\  

10 : 15

2 : 3

katen-ka-za [31]3 years ago
5 0

Answer:

+1 #

=5+1:3+1

=6:4

=3:2 #

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Which shows a way to take apart 8 .ans are. 9-9=0. 8-7=1. 9-8=1. 8+8=16.
Sergio039 [100]
<span>To take appart 8 means to subtract 8 from a number and then you will have two parts one with the number 8 and the other with the difference. So, if you want to take appart 8 from 9, you make 9 - 8 = 1. Which means that you can have 8 and 1 sperated from 9. So the answer is the third option 9 - 8 = 1.</span>
3 0
3 years ago
Suppose you are managing 16 employees, and you need to form three teams to work on different projects. Assume that all employees
valentina_108 [34]

Answer:

4380 ways

Step-by-step explanation:

We have to form 3 project of 16 employees, they tell us that the first project must have 5 employees, therefore we must find the number of combinations to choose 5 of 16 (16C5)

We have nCr = n! / (R! * (N-r)!)

replacing we have:

1st project:

16C5 = 16! / (5! * (16-5)!) = 4368 combinations

Now in the second project we must choose 1 employee, but not 16 but 11 available, therefore it would be to find the number of combinations to choose 1 of 11 (11C1)

2nd project:

11C1 = 11! / (1! * (11-1)!) = 11 combinations

For the third project we must choose 10 employees, but since we only have 10 available, we can only do a combination of this, since 10C10 = 1, therefore:

3rd project: 1 combination

The total number of combinations fro selecting 16 employees for each project would be:

4368 + 11 + 1 = 4380 combinations, that is, there are 4380 different ways of forming projects with the given conditions.

3 0
3 years ago
Production of a gas flow meter takes place in two distinct operations. Measurements (n = 15) of the time required for the first
Karolina [17]

Answer:

a) P(a > 80) = 0.323

b) The 95% confidence interval = (73.40, 80.60)

c) The 95% confidence interval expresses that the mean of the distribution can always be found in the given range, with a 95% confidence level.

Step-by-step explanation:

X ~ (45, 4)

Y ~ (32, 2.5)

(X+Y) ~ (77, 6.5)

Let a = (X+Y)

a) Probability that the time required to complete both of those steps will exceed 80 min = P(a > 80)

This is a normal distribution problem

We then standardize 80 min time

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (a - μ)/σ = (80 - 77)/6.5 = 0.46

To determine the probability the time required to complete both of those steps will exceed 80 min = P(a > 80) = P(z > 0.46)

We'll use data from the normal probability table for these probabilities

P(a > 80) = P(z > 0.46) = 1 - P(z ≤ 0.46) = 1 - 0.677 = 0.323

b) 95% confidence interval for the expected total time required to produce one flow meter.

We need to obtain the margin of error

Margin of error = (critical value) × (standard error of the sample)

Critical value for a 95% confidence interval = critical value for a significance level of 5% = t(15-1, 0.05/2) = 2.145 (using the t-score since information on the population mean and standard deviation isn't known)

Standard error for the sample of sum of times = (standard deviation of the sum of times)/√n = (6.5/√15) = 1.678

Margin of error = 2.145 × 1.678 = 3.60

Limits of the confidence interval = (Sample mean ± margin of error)

Lower limit of the confidence interval = (Sample mean - margin of error) = 77 - 3.60 = 73.40

Upper limit of the confidence interval = 77 + 3.60 = 80.60

The confidence interval = (73.40, 80.60)

4 0
3 years ago
What is the slope of a line through (-3, 4) and<br> (5, 6)?
Likurg_2 [28]

Answer:

slope= x2- x1/y2 -y1

= 5-(-3)/6-4

8/2= 4

7 0
2 years ago
What is 5 to the power of 1 in expanded form​
fomenos

Answer:

5^1 in expended from is 5

hope it helps.

3 0
2 years ago
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