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3 years ago

10

Help please it would really help! Please I'll give a brainliest for the best and correct answer!

2 answers:

Effectus [21]3 years ago

8 0

The answer is D. Trust me. I took this test.

iren [92.7K]3 years ago

6 0

The answer to your question is C. I hope this has helped

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If a ray divides an angle into two complementary angles, then the original angle is a right angle

lilavasa [31]

No as complementary angles add up to whisk 180 degrees, however supplementary angle would be true for this question

5 0

2 years ago

Read 2 more answers

What is the solution of x=2+ square root x-2?

alex41 [277]

So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

$x-2=\sqrt{x-2}$

Next, square both sides:

$(x-2)^2=x-2\\(x-2)(x-2)=x-2\\x^2-4x+4=x-2$

Next, subtract x and add 2 to both sides of the equation:

$x^2-5x+6=0$

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

$x^2-2x-3x+6=0$

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

$x(x-2)-3(x-2)=0$

Now you can rewrite the equation as $(x-3)(x-2)=0$

Now, apply the Zero Product Property and solve for x as such:

$x-3=0\\x=3\\\\x-2=0\\x=2$

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

$2=2+\sqrt{2-2}\\2=2+\sqrt{0}\\2=2+0\\2=2\ \textsf{true}\\\\3=2+\sqrt{3-2}\\3=2+\sqrt{1}\\3=2+1\\3=3\ \textsf{true}$

Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>

8 0

3 years ago

Plz need helpkkkkkssosp

Sholpan [36]

All of these answers are right

4 0

3 years ago

Find the distance between the pair of points.

SVEN [57.7K]

Answer:

Distance is $\sqrt{290}$ units

Step-by-step explanation:

Use the distance formula which is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where $d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$

We are given that $(x_1,y_1)$ is $(-6,-23)$ and $(x_2,y_2)$ is $(-23,-24)$ , therefore the distance between the two points is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(-23-(-6))^2+(-24-(-23))^2}$

$d=\sqrt{(-23+6))^2+(-24+23))^2}$

$d=\sqrt{(-17)^2+(-1)^2}$

$d=\sqrt{289+1}$

$d=\sqrt{290}$

Therefore, the distance between $(-6,-23)$ and $(-23,-24)$ is $\sqrt{290}$ units.

3 0

2 years ago

victor needs 30 feet of rope. the rope he want to buy is sold by the yard. he know that there are 3 feet in the 1 yard. how many

solmaris [256]

Answer: 10 yards

Step-by-step explanation:

Covert 30 feet into yards to find how many yards he should buy.

$\frac{30}{3} = \frac{x}{1}$ Solve by cross product

3x = 30

x = 10

3 0

3 years ago