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Degger [83]
3 years ago
10

Help please it would really help! Please I'll give a brainliest for the best and correct answer!

Mathematics
2 answers:
Effectus [21]3 years ago
8 0
The answer is D. Trust me. I took this test.
iren [92.7K]3 years ago
6 0
The answer to your question is C. I hope this has helped
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PLZZZ HELP IM IN A RUSH
cupoosta [38]
1/3 - 2/9 - 1/3

= -2/9
(Decimal: -0.222222)
4 0
2 years ago
Determine the direction that is parábola opens: y=4x^2+8x+2
marissa [1.9K]
It should open up because the a which is 4 is positive
5 0
3 years ago
Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distanc
Anna11 [10]

Answer:

The final velocity v is 21.74 m/s.

Step-by-step explanation:

Given:

\textrm{initial velocity} = u = 9\ m/s\\\textrm{acceleration} = a = 7\ m/s^{2}\\\textrm{distance} = s = 28\ m

To find:

\textrm{final velocity} = v = ?

Solution:

As we know the third equation of motion is represented as

v^{2} = u^{2} + 2\times a\times s\\

Substituting the values u, a and s in the above equation we get

v^{2} = 9^{2} + 2\times 7\times 28\\ =81 + 392\\=473\\

v =\±\sqrt{473} \\v =\sqrt{473} \ \textrm{as acceleration is positive v is also positive}\\v = 21.74\ m/s

7 0
3 years ago
Why are all the questons just for 5 points no one choses higher
ValentinkaMS [17]

Answer:

I don't know I want even let me choose 5

3 0
2 years ago
At the beginning of an experiment, the number of bacteria in a colony was counted at time t=O. The number of bacteria in the col
yan [13]

Answer:

1092

Step-by-step explanation:

We have been given that the number of bacteria in the colony t minutes after the initial count modeled by the function B(t)=9(3)^t. We are asked to find the average rate of change in the number of bacteria over the first 6 minutes of the experiment.

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

Upon substituting our given values, we will get:

\text{Average rate of change}=\frac{b(6)-b(0)}{6-0}

\text{Average rate of change}=\frac{9(3)^6-9(3)^0}{6}

\text{Average rate of change}=\frac{9(729)-9(1)}{6}

\text{Average rate of change}=\frac{6561-9}{6}

\text{Average rate of change}=\frac{6552}{6}

\text{Average rate of change}=1092

Therefore, the average rate of change in the number of bacteria is 1092 bacteria per minute.

8 0
2 years ago
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