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Dahasolnce [82]
3 years ago
5

State the angle relationship and state the measure of each angle indicated that makes lines u and v

Mathematics
1 answer:
vlabodo [156]3 years ago
7 0

Answer:

Q9. ?=53° (corr angles, u//v)

Q10. ?=58° (alt angles, u//v)

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Round 9.77 to the nearest tenth
djyliett [7]
9.77 to the nearest tenths

first, find the number that is in the tenths place....it is 7....now look at the number directly to the right of it....if that number is 5 or greater, u would round that 7 up to an 8...but if that number is 4 or below, ur 7 would stay the same.
So the number directly to the right of 7 is 7...and since it is greater then 5, u have to round the 7 in the tenths place up to 8.

solution is : 9.8
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3 years ago
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How is combining "like terms" similar to adding and subtracting whole numbers?
arsen [322]
Because like terms you add or subtract together to make it easier to do the problem. just like you do with whole numbers. you add an subtract to make the answer simpler.
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3 years ago
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Evaluate the expression. Simplify your answer. (-1/6)3
Eva8 [605]

Answer:

-1/216

Step-by-step explanation:

You have to look at the base and if the base is negative then you have to look at the exponent and if its a odd number then it will be a negative.

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3 years ago
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How can the area of this triangle be determined by forming a rectangle? Select from the drop-down menus to correctly complete th
Nuetrik [128]

The area of the triangle can be found by copying the triangle and putting the bases together such that it forms the diagonals of the triangle.

<h3>What is the area of the triangle?</h3>

The area of the triangle is half the product of the height of the triangle and the base of the triangle.

As we know that the area of a rectangle is double the area of a triangle,

therefore, in order to calculate the area of a triangle we need to convert it to a rectangle and then divide the area of the rectangle by 2.

Also, we know that the diagonal of a rectangle divides it into two equal triangles, therefore, we will put the triangle along the diagonal of the base.

Thus, to find the area of the triangle we will copy the triangle and put the base of the together such that it forms the diagonals of the triangle.

Since the triangles are put on each other along the base, therefore, the height(h) of the triangle will be the length of the rectangle, and the breadth of the triangle will be equal to the base of the triangle(b).

Learn more about Area of Triangle:

brainly.com/question/15442893

8 0
2 years ago
A 15 kilogram object is suspended from the end of a vertically hanging spring stretches the spring 1/3 meters. At time t = 0, th
Yuri [45]

Answer:

15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = ± 170 cos(5t)

y(0)=0, y'(0)=0

Step-by-step explanation:

See the attached image

This problem involves Newton's 2nd Law which is: ∑F = ma, we have that the acting forces on the mass-spring system are: F_{r} (t) that correspond to the force of resistance on the mass by the action of the spring and F(t) that is an external force with unknown direction (that does not specify in the enounce).

For determinate F_{r} (t) we can use Hooke's Law given by the formula F_{r} (t) = k y(t) where k correspond to the elastic constant of the spring and y(t) correspond to  the relative displacement of the mass-spring system with respect of his rest state.

We know from the problem that an 15 Kg mass stretches the spring 1/3 m so we apply Hooke's law and obtain that...

k = \frac{F_{r}}{y} = \frac{mg}{y} = \frac{15 Kg (9.81 \frac{m}{s^{2} } )}{\frac{1}{3} m}  = 441.45 \frac{N}{m}

Now we apply Newton's 2nd Law and obtaint that...

F_{r} (t) ± F(t) = ma(t)

F_{r} (t) = ky(t) = 441.45y(t)

F(t) = 170 cos(5t)

m = 15 kg

a(t) = \frac{d^{2}y(t)}{dt^{2} }

Finally... 15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = ± 170 cos(5t)

We know from the problem that there's not initial displacement and initial velocity, so... y(0)=0 and y'(0)=0

Finally the Initial Value Problem that models the situation describe by the problem is

\left \{ 15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = \frac{+}{} 170 cos(5t) \atop {y(0)=0, y'(0)=0\right.

6 0
3 years ago
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