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2 years ago

State the angle relationship and state the measure of each angle indicated that makes lines u and v

Mathematics

1 answer:

vlabodo [156]2 years ago

7 0

Answer:

Q9. ?=53° (corr angles, u//v)

Q10. ?=58° (alt angles, u//v)

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What is the answer 3x+(x-8)=120

Yuliya22 [10]

Combine like terms.

3x+(x-8)= 120

4x-8= 120

Add 8 to both sides.

4x= 128

Divide by 4 into both sides.

x= 32

I hope this helps!
~cupcake

8 0

3 years ago

The regular price of a dvd is $24?. During a sale, the price of a dvd is marked down 30%. What will the sale price of the dvd?

Tatiana [17]

If a $24 dvd is marked down by 30% then the cost of the dvd would be 70% of the original cost. 100% - 30% = 70%

70% of 24 can be expressed as 0.7 x 24.

The answer is $16.80.

Hope this helps :)

4 0

3 years ago

Which system of equations is equivalent to the system of equations shown?

Ivanshal [37]

<span>I can solve for x and y
A) 2x - 4y = 12
A) 2x = 4y + 12
A) x = 2y + 6
Substituting into B
B) 3* (2y +6) - 5y = 20
B) 6y + 18 -5y = 20
B) y = 2
B) x = 10

</span>

4 0

3 years ago

Factor the expression using the GCF.<br><br> 50x−60

aniked [119]

<h2>I Think it might be this hope you are helped by this</h2><h2></h2><h2>10(5x−6)</h2>

8 0

2 years ago

Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0

3 years ago