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sattari [20]
3 years ago
13

Example2 (3x+11)=10​

Mathematics
2 answers:
Bumek [7]3 years ago
6 0

Answer:

x = -2

Step-by-step explanation:

2 (3x+11)=10​

Divide each side by 2

2/2 (3x+11)=10​/2

3x+11 = 5

Subtract 11 from each side

3x+11-11 = 5-11

3x = -6

Divide each side by 3

3x/3 = -6/3

x = -2

Digiron [165]3 years ago
6 0

Answer:

<h3>2{3x+11}=10</h3><h3>= 2{11+3x}=10</h3><h3>{2×11 +2×3x}=10</h3><h3>{22+6x}=10</h3><h3>6x =10-22</h3><h3>6x=-12</h3><h3>x = 6 ÷ -12</h3><h3>= x = -2</h3><h2><u><em>hope this help's u </em></u></h2><h2><u><em>if it does so please mark me as brainiest </em></u></h2>
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First we assume that this is equal to zero

so what we notice is this is a sum of 2 perfect cube

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125x^3+343=
(5x)³+(7)³=(5x+7)(25x²-35x+49)

now solve the part in second parenthasees because we can see that the first parenthasees (5x+7) is going to have a real root

remember quadratic formula

for ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
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b=-35
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x=\frac{-(-35)+/- \sqrt{(-35)^2-4(25)(49)} }{2(25)}
x=\frac{35+/- \sqrt{1225-4900} }{50}
x=\frac{35+/- \sqrt{-3675} }{50}
x=\frac{35+/- (\sqrt{3675})( \sqrt{-1}) }{50}
x=\frac{35+/- (\sqrt{3675})(i) }{50}
x=\frac{35+/- 35i\sqrt{3} }{50}
x=\frac{7+/- 7i\sqrt{3} }{10}

the comlex roots are

x=\frac{7+ 7i\sqrt{3} }{10} and \frac{7- 7i\sqrt{3} }{10}




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