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AysviL [449]
2 years ago
5

I need help I don’t understand

Mathematics
1 answer:
aleksklad [387]2 years ago
7 0
<h3><em>1) 0.7</em></h3><h3><em>2) 0.42</em></h3><h3><em>3) 0.25</em></h3><h3><em>4) 0.375</em></h3><h3><em>5) 0.33</em></h3><h3><em>6) 0.071</em></h3><h3><em>7) 0.775</em></h3><h3><em>8) 0.775</em></h3><h3><em>9) 0.682</em></h3><h3><em>10) 0.791</em></h3><h3><em>HOPE IT HELPS !!!</em></h3>

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Show working please!
Nina [5.8K]
You do -2 plus 4. Answer is 2.
Then do 2-(-2) which is 0.
The final answer is 2.
7 0
3 years ago
Brian has $30 in his piggy bank. He earns $10 a week at his job.
sleet_krkn [62]

Answer:

B. 2 weeks

Step-by-step explanation:

1st week

Brian will have $40

Sarah will have $30

2nd week

Brian will have $50

Sarah will have $50

3 0
3 years ago
Read 2 more answers
Consider a collection of envelopes consisting of 1 red envelope, 3 blue envelopes, 2 green envelopes, and 3 yellow envelopes if
nasty-shy [4]

Answer:

the probability that at least one envelope is a yellow envelope is 16/21

Step-by-step explanation:

The probability that at least one envelope is a yellow envelope is P(Y);

P(Y) = 1 - P(Y)'

P(Y)' is the probability that no envelope is a yellow envelope.

Given;

red envelope = 1

blue envelopes = 3

green envelopes = 2

yellow envelopes = 3

Total = 9

Number of non-yellow envelope = 9 -3 = 6

(6 envelope are not yellow)

P(Y)' = P1 × P2 × P3

Since there is no replacement;

P(Y)' = 6/9 × 5/8 × 4/7

P(Y)' = 5/21

From equation 1;

P(Y) = 1 - 5/21

P(Y) = 16/21

the probability that at least one envelope is a yellow envelope is 16/21.

8 0
3 years ago
Just got switched to a new math class.... I need wit these two questions....
umka2103 [35]
I can’t see it needs better lighting
8 0
2 years ago
(d) Given that n(§) = 96, n(A) = 50 and n(B) = 60. Find the maximum and minimum values for n(An B).
frez [133]

Step-by-step explanation:

the max. value is when the smaller set (A) is completely contained in the larger set (B).

then n(A n B) is n(A) = 50.

the set intersection between A and B cannot get bigger than that. or A gets bigger ...

after all, the intersection means it is a set of all elements that exist in BOTH sets.

but then there must be other elements besides A and B in the universal set too, because n(universal set) = 96, and n(A u B) would be only 60.

the min. value could be the empty set or 0. but because n(universal set) = 96, and n(A) + n(B) = 110 and larger than 96, it means that there have to be some shared elements. at least 110 - 96 = 14 elements.

in this case there cannot be other elements in the universal set than A and B. and n(universal set) = n(AuB) = 96.

3 0
1 year ago
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