$D:x>0 \wedge x+15>0\\
D:x>0 \wedge x>-15\\
D:x>0\\\\
\log_4x+\log_4(x+15)=2\\
\log_4x(x+15)=2\\
4^2=x(x+15)\\
16=x^2+15x\\
x^2+15x-16=0\\
x^2-x+16x-16=0\\
x(x-1)+16(x-1)=0\\
(x+16)(x-1)=0\\
x=-16 \vee x=1\\
-16\not \in D \Rightarrow \boxed{x=1}$

7 0

3 years ago

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A walker and a cyclist are 45 miles apart. They move towards each other with speeds of 5 mph and 10 mph respectively. In how man

Ymorist [56]

Answer: they will meet after 3 hours.

Step-by-step explanation:

Let t represent the number of hours it will take them to meet.

A walker and a cyclist are 45 miles apart. If they move towards each other, in t hours, they would have covered a total of 45 miles

Distance = speed × time

They move towards each other with speeds of 5 mph and 10 mph respectively. It means that the distance covered by the walker in t hours is 5 × t = 5t

Also, the distance covered by the cyclist in t hours is 10 × t = 10t

Since the total distance covered us 45 miles, then

5t + 10t = 45

15t = 45

t = 45/15

t = 3 hours

4 0

3 years ago