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Ivenika [448]
3 years ago
7

Find the sum 7+101/2+14+.........+84​

Mathematics
1 answer:
rewona [7]3 years ago
3 0

Answer: 155.5 Is your sum! (❤´艸`❤)

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24 mouths have passed

Step-by-step explanation:

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Question set 2: Many species of terrestrial tree frogs that hibernate at or near the ground surface can survive prolonged exposu
joja [24]

Answer:

0.86

Step-by-step explanation:

The z-score we need to make the comparison is given by

\bf z=\frac{-2.05-(-2)}{\sigma/\sqrt{n}}

where

\bf \sigma= the standard deviation established in the study

n = the sample size

\bf z=\frac{-2.05-(-2)}{0.3/\sqrt{42}}=-1.0801

and for the Normal distribution N(0,1) we want to find  

<em>P(X > -1.0801) </em>

By using a spreadsheet or the table attached, we find that

P(X > -1.0801) = 0.86

(See picture attached)

7 0
3 years ago
RDY AND NDA are what?
madam [21]

Answer:

Vertical and Supplementary

Step-by-step explanation:

Vertical:

each of the pairs of opposite angles made by two intersecting lines.

Supplementary:

Two Angles are Supplementary when they add up to 180 degrees. These two angles (140° and 40°) are Supplementary Angles, because they add up to 180°: Notice that together they make a straight angle. But the angles don't have to be together.


8 0
3 years ago
Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and
zzz [600]

Answer:

\bold{sin(38^\circ)=cos(52^\circ)}

Step-by-step explanation:

Given that \triangle KJL is a right angled triangle.

\angle JKL = 52^\circ\\\angle KLJ = 38^\circ

and

\angle KJL = 90^\circ

Kindly refer to the attached image of \triangle KJL in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given \triangle KJL.

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

cos\theta =\dfrac{Base}{Hypotenuse}

cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}....... (2)

By (1) and (2):

sin(38°) \neq cos(38°).

cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL} ...... (3)

Comparing equations (1) and (3):

we get the both are same.

\therefore \bold{sin(38^\circ)=cos(52^\circ)}

6 0
3 years ago
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