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Doss [256]
3 years ago
13

Algebra 1 CR-8

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
4 0

\mathrm{Domain\:of\:}\:x^2+2x-15\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

\mathrm{Range\:of\:}x^2+2x-15:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:-16\:\\ \:\mathrm{Interval\:Notation:}&\:[-16,\:\infty \:)\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:x^2+2x-15:\quad \mathrm{X\:Intercepts}:\:\left(3,\:0\right),\:\left(-5,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:-15\right)

\mathrm{Vertex\:of}\:x^2+2x-15:\quad \mathrm{Minimum}\space\left(-1,\:-16\right)

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Answer:

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Step-by-step explanation:

Given the simultaneous equation;

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6x+4y=10.... 2

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9y = 11

y = 11/9

Substitute y = 11/9 into 1;

From 1;

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-6x + 5(11/9) = 1

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-6x = (9-55)/9

-6x = -46/9

x = -46/-54

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The solution to the system of equation is (23/27, 11/9)

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3 years ago
Use a(x) and b(x) shown below to evaluate the given expressions.
AnnZ [28]

Hello!


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