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Doss [256]
3 years ago
13

Algebra 1 CR-8

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
4 0

\mathrm{Domain\:of\:}\:x^2+2x-15\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

\mathrm{Range\:of\:}x^2+2x-15:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:-16\:\\ \:\mathrm{Interval\:Notation:}&\:[-16,\:\infty \:)\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:x^2+2x-15:\quad \mathrm{X\:Intercepts}:\:\left(3,\:0\right),\:\left(-5,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:-15\right)

\mathrm{Vertex\:of}\:x^2+2x-15:\quad \mathrm{Minimum}\space\left(-1,\:-16\right)

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write an algebraic expression for this word problem. An orange contains 62 calories which is x fewer calories than a nectarine.
nasty-shy [4]

Answer:

n = 62 + x

Step-by-step explanation:

From the problem given, it is clear that the orange has LESS calories than a nectarine. <em>HOW much less? "x" less.</em>

<em />

Also, orange has 62 calories. So, nectarine MUST HAVE 62 + x calories.

<em>If we let nectarine's calories be n, we can write:</em>

<em>n = 62 + x</em>

5 0
3 years ago
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kotykmax [81]
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4 0
4 years ago
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lbvjy [14]

Answer:

Step-by-step explanation:

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5 0
3 years ago
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G(x) =F(x-8) statements
Brilliant_brown [7]

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ikadub [295]
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3 years ago
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