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OleMash [197]
3 years ago
12

I NEED HELP!!!!!!!!!!!!! A spaceship needs to travel 5⁄7 of a light-year to get to the moon. The spaceship traveled 1⁄3 of a lig

ht-year before stopping at a space station to get fuel. How much further must the spaceship travel to get to the moon?
Mathematics
2 answers:
LenKa [72]3 years ago
6 0
It takes 2/3 of light 
erica [24]3 years ago
3 0
The spaceship must travel 2/3 of a light to get to the moon. Hope this helps!
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Answer:

1. ║u-z║= 5.66

2.║v-w║=6.0

3. ║w-u║=6.08

4.║v-u║=7.81

Step-by-step explanation:

The vectors are given as;

u = <-1, -3>, v = <5,-8>, w = <5, -2>, and z = <3, 1>.

To find the magnitude of the vectors;

1. ║u-z║

<-1 - 3> = <-4  and < -3 - 1> = <-4

║<-4,-4> ║= √{ -4²+-4²} = √32 = 5.66

2.║v-w║

   <5,-8> - <5,-2>

   <5-5> , <-8--2>

   <0,-6>

    ║<0,-6>║= √{0²+ -6²} = √36 = 6

3. ║w-u║

    <5,-2> - <-1,-3>

    <5--1> , <-2--3>

    <6,1>

    ║6,1║= √{6²+1²} = √36+1 = √37 = 6.08

4.║v-u║

   <5,-8> - <-1,-3>

    <5--1> , <-8--3>

    < 6 , -5 >

    ║6,-5║= √{6²+-5²} = √36+25 =√61 = 7.81

   

   

   

   

   

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