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jeyben [28]
3 years ago
14

Which expression is equal to 45+27?

Mathematics
2 answers:
lawyer [7]3 years ago
7 0
This answer would be b because 9(5+3)=72
And 45+27=72
labwork [276]3 years ago
6 0

Answer:

B

Step-by-step explanation:

45+27=72

A- 15 times 9 equals 135

B- 8 times 9= 72

C 45 times 18 equals 810,

D- 14 times 12 equals 68

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Suppose that the mean score of a class of 32 students was 74. the 19 male students in the class had a mean score of 70. what was
andrew-mc [135]
Mean = sum of values / number of values
74 = x/32
2368 = x

70 = y/19
1330 = y

mean for female students = (2368 - 1330)/(32-19) = 79.85
5 0
3 years ago
Least to greatest -6.8,|-23/4|,0,-14.4,|-1.9|,5.4
IrinaVladis [17]

Answer:

From Least to Greatest: -14.4, -6.8, -23/4, -1.9, 0, 5.4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the diffrence between 6 thirty-sixes and 4 thirty-sixes.?
Lilit [14]
6 thirty-sixes -4 thirty-sixes = 2 thirty-sixes
2 thirty-sixes = 2•36 = 72
6 0
3 years ago
Consider the linear system of equations. y = –x + 9 y = 0.5x – 6 If the solution is (a,–1), what is a? a =
timofeeve [1]

Answer:

a = 10

Step-by-step explanation:

From the solution given, x = a and y = -1

Substitute for x and y in either of the equations

y = -x + 9

-1 = -a + 9

a = 9 + 1 = 10

4 0
3 years ago
In order to estimate the difference between the average hourly wages of employees of two branches of a department store, two ind
liberstina [14]

Answer:

Step-by-step explanation:

Hello!

You have two populations of interest and want to compare them. If you define the study variables as:

X₁: average hourly wages of an employee of the Downtown store.

n₁= 25

X[bar]₁= $9

S₁= $2

X₂: average hourly wages of an employee of the North Mall store.

n₂= 20

X[bar]₂= $8

S₂= $1

Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:

95% CI for μ₁ - μ₂

(X[bar]₁-X[bar]₂) ± t_{n_1+n_2-2; 1-\alpha /2} * (Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } )

Sa^2= \frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}

Sa^2= \frac{24*4+19*1}{25+20-2}= 2.67

Sa= 1.64

t_{n_1-n_2-2;1-\alpha /2} = t_{43; 0.975} = 2.017

(9-8)±2.017*(1.64*\sqrt{\frac{1}{25} +\frac{1}{20} } )

[0.007636;1.9923]

I hope it helps!

6 0
3 years ago
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