Mean = sum of values / number of values
74 = x/32
2368 = x
70 = y/19
1330 = y
mean for female students = (2368 - 1330)/(32-19) = 79.85
Answer:
From Least to Greatest: -14.4, -6.8, -23/4, -1.9, 0, 5.4
Step-by-step explanation:
6 thirty-sixes -4 thirty-sixes = 2 thirty-sixes
2 thirty-sixes = 2•36 = 72
Answer:
a = 10
Step-by-step explanation:
From the solution given, x = a and y = -1
Substitute for x and y in either of the equations
y = -x + 9
-1 = -a + 9
a = 9 + 1 = 10
Answer:
Step-by-step explanation:
Hello!
You have two populations of interest and want to compare them. If you define the study variables as:
X₁: average hourly wages of an employee of the Downtown store.
n₁= 25
X[bar]₁= $9
S₁= $2
X₂: average hourly wages of an employee of the North Mall store.
n₂= 20
X[bar]₂= $8
S₂= $1
Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:
95% CI for μ₁ - μ₂
(X[bar]₁-X[bar]₂) ± 


Sa= 1.64

(9-8)±2.017*
[0.007636;1.9923]
I hope it helps!