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irakobra [83]
3 years ago
14

WHAT ARE THE ELEMENTS NEEDED TO PROVE SIMILARITY BETWEEN TWO FIGURES? EXPLAIN.

Mathematics
1 answer:
kati45 [8]3 years ago
4 0

Answer:

AAA (Angle Angle Angle) Proving that the angles are the same (Or of the same ratio if diluted), if this is true, the two figures are similar.

SSS (Side Side Side) Proving all the sides are the same size (Or again of the same ratio) also proves similarity.

SAS (Side Angle Side) If two sides and the angle in between are the same, then the triangles are similar.

Step-by-step explanation:

EX)

Triangle A has sides 10, 5, and 12

Triangle B has sides 20, 10, and 24

The relationship is the same between both triangles, just that the sides are multiplied by 2. This is SSS

If Triangle A has two sides 5 and 10 with an angle of 25 degrees, then Triangle B must have that same angle alongside those two sides, or at least a consistent ratio if diluted. Proof SAS

If Triangle A and B have the same angles, they are similar.

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According to a random sample taken at 12​ A.M., body temperatures of healthy adults have a​ bell-shaped distribution with a mean
mrs_skeptik [129]

Answer:

There are 89% of healthy adults with body temperatures that are within 3 standard deviations of the​ mean

The minimum value that is within 3 standard deviations of the mean is 96.57.

The maximum value that is within 3 standard deviations of the mean is 100.11.

Step-by-step explanation:

Chebyshev's theorem states that a minimum of 89% of the values lie within 3 standard deviation of the mean.

So

Using​ Chebyshev's theorem, what do we know about the percentage of healthy adults with body temperatures that are within 3 standard deviations of the​ mean?

There are 89% of healthy adults with body temperatures that are within 3 standard deviations of the​ mean.

What are the minimum and maximum possible body temperatures that are within 3 standard deviations of the​ mean?

We have that the mean \mu is 98.34 and the standard deviation \sigma is 0.59. So:

Minimum

Mi = \mu - 3\sigma = 98.34 - 3(0.59) = 96.57

Maximum

Ma = \mu + 3\sigma = 98.34 + 3(0.59) = 100.11

8 0
3 years ago
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Tyler missed 8 out of 30 questions on a math test. What percent of the problems did he get CORRECT?
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22/30*100=73 1/3

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