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ikadub [295]
2 years ago
6

The most common injuries that can occur from sports.

Mathematics
2 answers:
Otrada [13]2 years ago
6 0
I think it's a hamstring strain.
Romashka [77]2 years ago
5 0
Well, there is a wide variety, actually. There could be:
- head injuries
- knee/wrist injuries
- sprains
- joint wrenches
- pulled muscles
- broken bones
- basically crashing into other players at high speeds

I hope this helps and have a good night! :D
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a jogger ran 3 miles due east of his house. then he ran 5 miles at a heading of 30 east of north. how far is he from his house a
Jobisdone [24]
Let's say her speed was x miles/hour during the first 3 miles runThen, time = distance/speedt1 = 3/x       eq1 In the next 4 miles run, her speed = x-1 miles/hourTime taken:t2 = 4/(x-1)      eq2 Now, total time:t1 + t2 = 1 3/5 hourssubstitute t1 and t2 from eqs. 1 and 2 3/x + 4/(x-1) = 1 3/5=> 3/x + 4/(x-1) = 8/5
=> 3(x-1) + 4x = 8x(x-1)/5=> 35x - 15 = 8x2 - 8x=> 8x2 - 43x + 15 = 0=> (8x-3)*(x-5) = 0=> x = 3/8 or 5 miles/hourx can not be 3/8 miles/hour because in that case, the speed during 4 miles run would be 3/8-1 = negative numberi.e. speed during 3 miles segment = 5 miles/hourand speed during 4 miles segment = 5-1 = 4 miles/hour
5 0
3 years ago
MANY POINTS! PLEASE HELP
Vlad1618 [11]

Answer:

B.  51.7699^2

Step-by-step explanation:

Last 2 wrong because it is positive.

101.... is not the definite integral for the curve

51... purrfecto

3 0
1 year ago
The expression 4x/5-2x/3 is equivalent to
slava [35]
12x/15-10x/15

=2x/15 is your answer
5 0
3 years ago
Read 2 more answers
A survey found that​ women's heights are normally distributed with mean 63.3 in. and standard deviation 2.7 in. The survey also
mylen [45]

Answer:

A) There is a 100% chance of meeting the height requirement for women.

B) There is a 99.89% chance of meeting the height requirement for men.

C) New height requirements are:

71.9 inches for men and 58.9 inches minimum for women.

At least 58.9 inches and at most 71.9 inches.

Step-by-step explanation:

This question involves finding z values which tell us the percentage from 0 to x.

z = (x-μ)/σ

A) In this question, the minimum sample point is 4 ft 9 inches or converting to inches, we have;(4*12) + 9 =57 inches.

The maximum sample point is 6 ft 4 inches which in inches gives; (6*12) + 4 = 76 inches

For the minimum point;

z = (57 - 63.3)/2.7 = -2.33

From the z-distribution table, this equates to 0.0099.

The maximum;

z = (76 - 63.3)/2.7 = 4.70

From the z-table, it gives 0.999.. Basically 100%.

So there is a 100% chance of meeting the height requirement for women.

B) For men;

the minimum z = (57 - 67.3)/2.8 = -3.68 which gives 0.00012 from the z-distribution table.

The maximum;

z = (76 - 67.3)/2.8 = 3.07 which gives 0.9989 from the z-distribution table. Basically, 99.89%.

So there is a 99.89% chance of meeting the height requirement for men.

C) To exclude the tallest 5% of men, we need to find the z-value for 0.95 and then solve for x.

Thus from the z-table, z = 1.65. So;

1.645 = (x - 67.3)/2.8

4.606 = x - 67.3

x = 67.3 + 4.606

x ≈ 71.9 inches for men.

So, Current minimum is okay.

To exclude the shortest 5% of women, we need to find the z for 0.05.

From the z-distribution table, it has a value of -1.645. So;

-1.645 = (x - 63.3)/2.7

-4.4415 = x - 63.3

x = 63.3 - 4.4415

x ≈ 58.9 inches minimum.

So, Current maximum is okay.

5 0
3 years ago
PLz anwser will mark brain list (find the area)
eduard

Answer:

A = 24

Area for a triangle = 1/2 b * h

5 0
2 years ago
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