Only three rectangles are needed, the one at the bottom and the two at the sides.
I hope this helps.
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Let
x-------> the width of the rectangular area
y------> the length of the rectangular area
we know that
y=x+15------> equation 1
perimeter of a rectangle=2*[x+y]
2x+2y <= 150-------> equation 2
substitute 1 in 2
2x+2*[x+15] <=150--------> 2x+2x+30 <=150----> 4x <=150-30
4x <= 120---------> x <= 30
the width of the rectangular area is at most 30 ft
y=x+15
for x=30
y=30+15------> y=45
the length of the rectangular area is at most 45 ft
see the attached figure
the solution is<span> the shaded area</span>
Answer:
6ab(2a-3b-5b²)
Step-by-step explanation:
6(2a²b-3ab²-5ab³)
6a(2ab-3b²-5b³)
6ab(2a-3b-5b²)
Answer:
I. 5
Step-by-step explanation:
- 140° and 8x° are on the straight angle and they are both equal 180°
to find the value of x:
140 + 8x = 180
8x = 180 - 140
8x = 40
x = 40/8
x = 5
30 * 11.95 = 358.5 so mr kaplan will end up paying $358.5