Charles' weight = Edith's weight + 20% of Edith's weight
We'll use a variable to represent Edith's weight, x.
The decimal form of 20% is 0.2.
60 = x + 0.2x
60 = 1.2x
x = 50
Edith's weight is 50kg.
Hope this helps!
Answer:
are there any more details? cant solve anything from what you have provided
Step-by-step explanation:
Answer:
x^2 y ^4 ∛ [x^2 y ^2 ] is the answer that I got
Step-by-step explanation:
Answer:
Rise (y) over Run (x)
12-5
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3-1
7/2=m
Step-by-step explanation:
Answer:
40.1% probability that he will miss at least one of them
Step-by-step explanation:
For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
0.95 probaiblity of hitting a target
This means that ![p = 0.95](https://tex.z-dn.net/?f=p%20%3D%200.95)
10 targets
This means that ![n = 10](https://tex.z-dn.net/?f=n%20%3D%2010)
What is the probability that he will miss at least one of them?
Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So
![P(X = 10) + P(X < 10) = 1](https://tex.z-dn.net/?f=P%28X%20%3D%2010%29%20%2B%20P%28X%20%3C%2010%29%20%3D%201)
We want P(X < 10). So
![P(X < 10) = 1 - P(X = 10)](https://tex.z-dn.net/?f=P%28X%20%3C%2010%29%20%3D%201%20-%20P%28X%20%3D%2010%29)
In which
![P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401](https://tex.z-dn.net/?f=P%28X%20%3C%2010%29%20%3D%201%20-%20P%28X%20%3D%2010%29%20%3D%201%20-%200.5987%20%3D%200.401)
40.1% probability that he will miss at least one of them