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4 years ago

What is the square root of 37.

1 answer:

7 0

Because no perfect squares are factors of 37, the most simplified that the square root of 37 can get is

√37, or approximately 6.08

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Why are 1 4 9 16 and 25 called perfect squares

olga nikolaevna [1]

Perfect squares can be divided and multiplied by the same number to get the same number. For example 25/5=5. 5*5=25.
4/2=2, 2*2=4
1/1=1, 1*1=1
9/3=3, 3*3=9
16/4=4, 4*4=16.
Hence the perfect squares.

4 0

3 years ago

Read 2 more answers

Adding unlike fractions <br><br> 1/2+19/20

Nataly [62]

1/2 + 19/20
= 10/20 + 19/20
= 29/20

3 0

4 years ago

Read 2 more answers

The Angle of depression from the top of the flagpole to an object on the ground it's 33° if the object is 60 feet from the base

N76 [4]

Answer:

The flag pole is 38.96 feet tall.

Step-by-step explanation:

The angle of depression from the top of the flagpole to an object on the ground is 33°.

The object is 60 feet from the base of the cliff.

We need to find the height of the flag pole.

Here, base, B = 60 feet

We know that,

$\tan\theta=\dfrac{P}{B}$

Put all the values to find P.

$P=B\times \tan\theta\\\\P=60\times \tan(33)\\\\P=38.96\ ft$

So, the flag pole is 38.96 feet tall.

6 0

3 years ago

A shirt is priced at $24.95. If you have a coupon for 30% off, how much does the shirt cost after the coupon is applied?

kompoz [17]

It should be About $7.49

7 0

3 years ago

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Function rule and y intercept

stiks02 [169]

to get the equation for any straight line, all we need is two points from it, so hmmm say from this table let's use (2,0) and (6,-8)

$\bf \begin{array}{|r|r|r|r|r|r|} \cline{1-6} days&x&2&4&6&8\\ \cline{1-6} dollars&y&0&-4&-8&-12\\ \cline{1-6} \end{array}~\hfill (\stackrel{x_1}{2}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-8}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{2}}}\implies \cfrac{-8}{4}\implies \cfrac{\stackrel{rise}{-2}}{\underset{run}{1}}\implies \stackrel{slope}{-2}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-2}(x-\stackrel{x_1}{2}) \\\\\\ \stackrel{~\hfill y-intercept}{y=-2x\stackrel{\downarrow }{+4}}\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

6 0

4 years ago