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Naddik [55]
1 year ago
14

For questions 6 – 10, find the unknown side length. number 10

Mathematics
1 answer:
Sergeu [11.5K]1 year ago
3 0
Answer: \begin{gathered} s\text{ = 10}\sqrt{2}\text{    \lparen exact answer\rparen} \\ s\text{ = 14.142   \lparen decimal approx.\rparen} \end{gathered}

Explanation:

10) Given:

hypotenuse = 20

angle = 45°

To find:

length of s

angle = 45

opposite = side opposite the angle = s

To find the value of s, w will apply sine ratio (SOH)

sin\text{ 45 = }\frac{opposite}{hypotenuse}\begin{gathered} sin\text{ 45 = }\frac{s}{20} \\ s\text{ = 20sin45} \\ sin\text{ 45 = }\frac{\sqrt{2}}{2} \\  \\ s\text{ = 20}\times\frac{\sqrt{2}}{2} \\ s\text{ = 10}\sqrt{2}\text{    \lparen exact answer\rparen} \end{gathered}\begin{gathered} s\text{ = 20sin45} \\ s\text{ = 20\lparen0.7071\rparen} \\ s\text{ = 14.142   \lparen decimal approximation\rparen} \end{gathered}

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How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98
Irina18 [472]

Answer:

n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=1400 represent the sample standard deviation

n represent the sample size  

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be z_{\alpha/2}=2.33, replacing into formula (b) we got:

n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67

So the answer for this case would be n=67 rounded up

8 0
3 years ago
Please help asap !!!!
Allisa [31]
No solution
This will help I hope
8 0
3 years ago
If the textbook weight 19.6 newtons on venus, what is the strenght of gravity on that planet?
victus00 [196]

Answer:

8.91m/s²

Step-by-step explanation:

If you were referring to the question :

If a 2.2 kg textbook weighs 19.6 newtons on Venus, what is the strength of gravity on that planet then read on.

Weight is the force of gravity on an object and it can be computed using the formula:

W = mg

where:

W = weight (N)

m = mass (kg)

g = acceleration due to gravity

So we know the weight and the mass of the object, all we do is plug it into our formula and solve for what we do not know.

W = mg\\\\19.6N = (2.2kg)(g)\\\\ \dfrac{16.6N}{2.2kg} = g\\\\8.91m/s^{2} = g

6 0
3 years ago
URGENT!! GEOMETRY DILATIONS AND TRANSLATIONS!!! BRAINLIEST WILL BE GIVEN !! BOGUS ANSWERS WILL BE BLOCKED !!
nekit [7.7K]

The answer is the same as it was for your other posting of this question at brainly.com/question/10712448

dilation magnitude: 2/3

translation: 5 to the left and 4 down

4 0
2 years ago
What is the value of x?
skelet666 [1.2K]

Answer:

x = 20

Step-by-step explanation:

Since ΔACB ≅ ΔDCE then ∠A ≅ ∠D, that is

3x - 10 = 2x + 10 ( subtract 2x from both sides )

x - 10 = 10 ( add 10 to both sides )

x = 20

8 0
3 years ago
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