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seropon [69]
3 years ago
10

Write the interval (5 , 100) as an inequality and using set notation.

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
3 0

Answer:

5

Step-by-step explanation:

5 100

500

100

600

10000

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It is A)

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A large stand of fir trees occupies 24 hectares. The trees have an average density of 1 tree per 20m squared. A forester estimat
Leona [35]

Answer:

The yield of the stand if one-tenth of the trees are cut is 360000 board-feet.

Step-by-step explanation:

First, let is find the total amount of fir trees that occupies the area of 24 hectares. (1 hectare = 10000 square meters)

n = \sigma \cdot A

Where:

\sigma - Surface density, measured in trees per square meter.

A - Total area, measured in square meters.

Given that \sigma = \frac{1}{20}\,\frac{tree}{m^{2}} and A = 24\,h, the total amount of fir trees is:

n = \left(\frac{1}{20}\,\frac{trees}{m^{2}}  \right)\cdot (24\,h)\cdot \left(10000\,\frac{m^{2}}{h} \right)

n = 12000\,trees

It is known that one-tenth of the tress are cut, whose amount is:

n_{c} = 0.1 \cdot n

n_{c} = 0.1 \cdot (12000\,trees)

n_{c} = 1200\,trees

If each tree will yield 300 board-feet, then the yield related to the trees that are cut is:

y = S\cdot n_{c}

Where:

S - Yield of the tress, measured in board-feet per tree.

n_{c} - Amount of trees that will be cut, measured in trees.

If n_{c} = 1200\,trees and S = 300\,\frac{b-ft}{tree}, then:

y = \left(300\,\frac{b-ft}{tree} \right)\cdot (1200\,trees)

y = 360000\,b-ft

The yield of the stand if one-tenth of the trees are cut is 360000 board-feet.

8 0
3 years ago
Suppose the position of an object moving in a straight line is given by s (t )equals 4 t2+ 5 t+ 5. Find the instantaneous veloci
VLD [36.1K]

Answer:

v(t) = 8t +5

And that represent the instantaneous velocity at a given time t.

And then we just need to replace t =2 in order to find the instantaneous velocity and we got:

v(t=2) = 8*2 + 5 = 16+5 = 21

Step-by-step explanation:

For this case we have the position function s(t) given by:

s(t) = 4t^2 + 5t+5

And we can calculate the instanteneous velocity with the first derivate respect to the time, like this:

v(t) = s'(t)= \frac{ds}{dt}

And if we take the derivate we got:

v(t) = 8t +5

And that represent the instantaneous velocity at a given time t.

And then we just need to replace t =2 in order to find the instantaneous velocity and we got:

v(t=2) = 8*2 + 5 = 16+5 = 21

4 0
2 years ago
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