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3 years ago

7

Consider the following system of equations given in slope-intercept form. y=-3x+17 y = 5x - 23 Use the graphing calculator to de

termine the best window range to find the point of intersection. O -10 s x s 10, -10 s y < 10 O -20 s x s 0 -20 sy s 0 Oos** 20.0 sy s 20 O 20 s x s 40. 20 s ys 4O

2 answers:

Slav-nsk [51]3 years ago

5 0

Answer:

Consider the following system of equations given in slope-intercept form.

y = −1

3

x + 17,

y = 5x - 23

Step-by-step explanation:

Paladinen [302]3 years ago

4 0

Answer:

0<x<20, 0<y<20

Step-by-step explanation:

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In the following exercise, does the problem involve permutations or combinations? Explain your answer. One hundred people purc

Blizzard [7]

Answer: Permutation is involved , since order of prizes matters.

The number of different ways the prizes can be awarded =95060

Step-by-step explanation:

Given : Total number of people purchase lottery tickets =100

The number of prizes = 3

Since each prize can be claimed by only one person.

So order matters here, there for we use permutations .

The number of permutations of n objects taken m at a time is given by :-

$^nP_m=\dfrac{n!}{(n-m)!}$

Then, the number of different ways the prizes can be awarded :-

$^{100}P_{3}=\dfrac{100!}{(100-3)!}=\dfrac{100!}{97!}\\\\=100\times98\times97=950600$

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3 years ago

(43 points) In the US, 85% of the population has Rh positive blood. Suppose we take a random sample of 6 persons and let Y denot

VladimirAG [237]

Answer:

a) Binomial distribution with parameters p=0.85 q=0.15 n=6

b) 62.29%

c) 2.38%

d) See explanation below

Step-by-step explanation:

a)

We could model this situation with a binomial distribution

$P(6;k)=\binom{6}{k}p^kq^{6-k}$

where P(6;k) is the probability of finding exactly k people out of 6 with Rh positive, p is the probability of finding one person with Rh positive and q=(1-p) the probability of finding a person with no Rh.

So

$\bf P(Y=k)=\binom{6}{k}(0.85)^k(0.15)^{6-k}$

b)

The probability that Y is less than 6 is

P(Y=0)+P(Y=1)+...+P(Y=5)

Let's compute each of these terms

$P(Y=0)=P(6;0)=\binom{6}{0}(0.85)^0(0.15)^{6}=1.139*10^{-5}$

$P(Y=1)=P(6;1)=\binom{6}{1}(0.85)^1(0.15)^{5}=0.0000387281$

$P(Y=2)=P(6;2)=\binom{6}{2}(0.85)^2(0.15)^{4}=0.005486484$

$P(Y=3)=P(6;3)=\binom{6}{3}(0.85)^3(0.15)^{3}=0.041453438$

$P(Y=4)=P(6;4)=\binom{6}{4}(0.85)^4(0.15)^{2}=0.176177109$

$P(Y=5)=P(6;5)=\binom{6}{5}(0.85)^5(0.15)^{1}=0.399334781$

and adding up these values we have that the probability that Y is less than 6 is

$\sum_{i=1}^{5}P(Y=i)=0.622850484\approx 0.6229=62.29\%$

c)

In this case is a binomial distribution with n=200 instead of 6.

p and q remain the same.

The mean of this sample would be 85% of 200 = 170.

In a binomial distribution, the standard deviation is

$s = \sqrt{npq}$

In this case

$\sqrt{200(0.85)(0.15)}=5.05$

<em>Let's approximate the distribution with a normal distribution with mean 170 and standard deviation 5.05</em>

So, the approximate probability that there are fewer than 160 persons with Rh positive blood in a sample of 200 would be the area under the normal curve to the left of 160

(see picture attached)

We can compute that area with a computer and find it is

0.0238 or 2.38%

d)<em> In order to approximate a binomial distribution with a normal distribution we need a large sample like the one taken in c).</em>

In general, we can do this if the sample of size n the following inequalities hold:

$np\geq 5 \;and\;nq \geq 5$

in our case np = 200*0.85 = 170 and nq = 200*0.15 = 30

4 0

3 years ago

28÷x=168<br>What is the value of "x"

coldgirl [10]

It is 1/6 or .16 I used Photomath

7 0

3 years ago

Find the measure of the missing angles in the triangle below round your answer to the nearest degree

navik [9.2K]

Answer:

a. 40°

b. 21°

Step-by-step explanation:

a. Reference angle = θ

Opposite = 5

Adjacent = 6

Apply TOA:

$Tan (\theta) = \frac{Opp}{Adj}$

$Tan (\theta) = \frac{5}{6}$

$\theta = Tan^{-1}(\frac{5}{6})$

$\theta = 40$ (nearest degree)

b. Reference angle = x

Opposite = 5

Hypotenuse = 14

Apply SOH:

$Sin (x) = \frac{Opp}{Hyp}$

$Sin (x) = \frac{5}{14}$

$x = Sin^{-1}(\frac{5}{14})$

$x = 21$ (nearest degree)

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3 years ago

The ratio of girls to boys in a class is 5 to 4 if there are 20 boys then how many total students are in class

LuckyWell [14K]

answer:

36

explanation to answer:

6 0

4 years ago