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True [87]
3 years ago
9

-2 (4t-3)+6t=5t-2 solve

Mathematics
1 answer:
ElenaW [278]3 years ago
8 0
-8t+6+6t=5t-2
-2t+6=5t-2
-2t-5t=-2-6
-7t=-8
-7 -7
T=1.14 or 1 1/7
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According to a soccer coach, 75% of soccer players have had at least one sprained ankle. An athletic trainer would like to inves
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Answer:

H0 : μ = 0.75

H1 : μ > 0.75

Step-by-step explanation:

Given :

Sample size, n = 125

x = 99

Phat = x / n = 99 / 125 = 0.792

Population proportion, P = 0.75

The hypothesis :

Null hypothesis :

H0 : μ = 0.75

Alternative hypothesis ;

Egates the null hypothesis ; since the sample proportion is greater than the the population proportion or claim "; then we use the greater than sign.

H1 : μ > 0.75

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Karen gaines invested $15,000 in a money market account with an interest rate of 2.25% compounded semiannually. Five years later
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3 years ago
What is 80%of 1,60<br>will mark brainliest​
cluponka [151]

Answer:

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3 years ago
Find the height of a triangle with an area (A) of 35 square inches and base of 7 use the formula A= 1/2bh
slega [8]

Answer:

D. 10

Step-by-step explanation:

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3 years ago
Could someone help me rnnn?
GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola:  y=3x^2-4

Step-by-step explanation:

Given:

  • y-intercept of parabola: -4
  • parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola:  y=a(x-h)^2+k

(where (h, k) is the vertex and a is some constant)

Substitute point (0, -4) into the equation:

\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}

Substitute point (-2, 8) and ah^2+k=-4 into the equation:

\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}

Substitute point (1, -1) and ah^2+k=-4 into the equation:

\begin{aligned}\textsf{At}\:(1.-1) \implies a(1-h)^2+k &=-1\\a(1-2h+h^2)+k &=-1\\a-2ah+ah^2+k &=-1\\\implies a-2ah-4&=-1\\a(1-2h)&=3\end{aligned}

Equate to find h:

\begin{aligned}\implies a(1+h) &=a(1-2h)\\1+h &=1-2h\\3h &=0\\h &=0\end{aligned}

Substitute found value of h into one of the equations to find a:

\begin{aligned}\implies a(1+0) &=3\\a &=3\end{aligned}

Substitute found values of h and a to find k:

\begin{aligned}\implies ah^2+k&=-4\\(3)(0)^2+k &=-4\\k &=-4\end{aligned}

Therefore, the equation of the parabola in vertex form is:

\implies y=3(x-0)^2-4=3x^2-4

So the vertex of the parabola is (0, -4)

5 0
2 years ago
Read 2 more answers
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