Answer:
1800 miles
Step-by-step explanation:
No. of miles driven by Mr. Thomas in May = 75
It is given that miles driven in July is 6 times of miles driven by Mr. Thomas in May(75 miles).
Thus
No. of miles driven by Mr. Thomas in July = 6 * No. of miles driven by Mr. Thomas in May = 6*75 = 450 miles.
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Another condition given that miles driven in June is 4 times of miles driven by Mr. Thomas in July(450miles as calculated above).
Thus
No. of miles driven by Mr. Thomas in June = 4 * No. of miles driven by Mr. Thomas in July = 4* 450 miles = 1800 miles.
No. of miles driven by Mr. Thomas in June is 1800 miles.
<h3>
Answer:</h3>
A net is shown with 3 rectangles attached side by side all with width 2 centimeters. The length of the first and third rectangle is 9 centimeters and the middle is 7 centimeters. Attached to the middle rectangle below are 3 rectangles with a length of 7 centimeters. The width of these rectangles are 9 centimeters, 2 centimeters, and 9 centimeters.
<h3>
Step-by-step explanation:</h3>
The area of a rectangular prism is the area of 6 surfaces. That is, 3 pairs of surfaces. Each of the three pairs will have one of the sets of dimensions ...
- length × width
- length × height
- width × height
In order for a net to be a net useful for calculating the prism surface area, it must have 3 pairs of rectangles with these dimensions. The description above matches that requirement.
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Please note that no two surfaces with the same pair of dimensions are adjacent.
Answer:
Number line with open circle on 2 and shading to the right
Step-by-step explanation:
this is showing that it has to be greater than two and is going up on the number line
<span>Probability = 0.063
Fourth try = 0.0973
Let X be the number of failed attempts at passing the test before the student passes. This
is a negative binomial or geometric variable with x â {0, 1, 2, 3, . . .}, p = P(success) = 0.7
and the number of successes to to observe r = 1. Thus the pmf is nb(x; 1, p) = (1 â’ p)
xp.
The probability P that the student passes on the third try means that there were x = 2
failed attempts or P = nb(2, ; 1, .7) = (.3)2
(.7) = 0.063 . The probability that the student
passes before the third try is that there were two or fewer failed attmpts, so P = P(X ≤
2) = nb(0, ; 1, .7) + nb(1, ; 1, .7) + nb(2, ; 1, .7) = (.3)0
(.7) + (.3)1
(.7) + (.3)2
(.7) = 0.973 .</span>
