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PIT_PIT [208]
3 years ago
12

11 more than twice a number has the same value as 8 times the difference of the number and 5

Mathematics
1 answer:
masya89 [10]3 years ago
6 0

11+2x = 8*(x-5)

11+2x = 8x-40

11+40+2x = 8x-40+40

51+2x-2x=8x-2x

51 = 6x

51/6 = 6x/6

8.5 = x

Therefore, your number is 8.5.

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As shown in the diagram of the right triangles below, Triangle: ABC ~ Triangle: DEF, AB = 7x, BC = 4, DE = 7, EF = x. What is th
charle [14.2K]

since triangles are similar

4/x = 7x/7

=》 4/x = x

=》x^2 = 4

=》 x = 2

for right triangles a^2 = b^2+c^2

DF^2 = 7^2+2^2 = 53

=》 DF = 7.28

perimeter of DEF = 7 +2+7.28 = 16.28

8 0
3 years ago
15 roses cost 33.75 how much will 27 roses cost​
luda_lava [24]

Answer:

60.75

Step-by-step explanation:

First, you need to see how much one rose costs.

33.75/15 is 2.25

Next, you need to find out how many 27 roses costs.

2.25*27 is 60.75

Now you have your answer.

Hope this helps and is right!

5 0
2 years ago
What are the vertical and horizontal asymptotes for the function f(x)=<br> 3x2/x2-4
Alecsey [184]

Answer:  f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.

Step-by-step explanation:

Given function: f(x)=\dfrac{3x^2}{x^2-4}

The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.

i.e. x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2

Hence, f(x) will have vertical asymptotes at x=-2 and x=2.

To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.

So, the graph will horizontal asymptote at y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}

i.e. y=\dfrac{3}{1}=3

Hence, f(x) will have horizontal asymptote at y=3.

3 0
3 years ago
A person buys X meter for 5
Nady [450]

Step-by-step explanation:

I guess, it means every meter costs these amounts.

and the specified costs are not fit the whole bundle.

it is also unclear, if "half of it" means half of the original x meters, or half of the remaining meters (after selling 2/5 of the original meters). I assume the first.

so, we have

-5x

+ 2/5x × 5.5

+ 1/2x × 6.4

+ (10/10 - 4/10 - 5/10)x × 6 = + 1/10x × 6

= 120 ( a income minus costs is the profit, so balancing both sides in a "+" and "-" expression gives us the remaining profit).

about the line with the 1/10 :

the leftovers. 10/10 is the whole x at the beginning.

2/5 = 4/10.

1/2 = 5/10.

I brought all involved fractions to the same denominator of the smallest common multiple of 2 and 5 (10).

in full

-5x + (2/5)x×5.5 + (1/2)x×6.4 + (1/10)x×6 = 120

-5x + 2.2x + 3.2x + 0.6x = 120

-5x + 6x = 120

x = 120

so, he bought 120m in the first place.

8 0
3 years ago
Write the equation for the parabola that has x− intercepts (−2,0) and (4,0) and y− intercept (0,4).
seropon [69]

Answer:

y = -\frac{1}{2}(x^2-2x-8)

Simplified it is y=-\frac{1}{2}x^2+x+4

Step-by-step explanation:

The x-intercepts of a parabola form the factors of the equation. Since the x -intercepts are (-2,0) and (4,0) then the factors are (x+2) and (x-4). Factors are pieces which multiply to make the equation.

y=(x+2)(x-4)\\y=x^2+2x-4x-8\\y=x^2-2x-8

This is the standard form of the parabola ax^2+bx+c. Since the y-intercept of the parabola is (0,4) then a number must also be multiplied to it

y=a(x^2-2x-8)

We find a by plugging in x=0 and y=4.

4=a(0^2-2(0)-8)\\4=a(0-0-8)\\4=a(-8)\\\frac{4}{-8} = a\\\frac{-1}{2} = a

So the equation is y = -\frac{1}{2}(x^2-2x-8).

When simplified it is y=-\frac{1}{2}x^2+x+4


3 0
3 years ago
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