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3 years ago

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Please hurry, this is timed. RIGHT ANSWERS ONLY! I will give brainiest if correct.

1 answer:

Oksanka [162]3 years ago

6 0

Answer:

Yes you are correct.

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MZ2=<br> m23=<br> m24=<br> Help due today!!!

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3 years ago

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Cot theta is undefiend for theta

Elena-2011 [213]

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The radius of a spherical balloon is measured as 20 inches, with a possible error of 0.03 inch. Use differentials to approximate

soldi70 [24.7K]

Answer:

a) $V = 33510.322\,in^{3}$ , b) $A_{s} = 5026.548\,in^{2}$ , c) $\% V = 0.450\,\%$ , $\%A_{s} = 0.300\,\%$ .

Step-by-step explanation:

The volume and the surface area of the sphere are, respectively:

$V = \frac{4}{3}\pi \cdot r^{3}$

$A_{s} = 4\pi \cdot r^{2}$

a) The volume of the sphere is:

$V = \frac{4}{3}\pi \cdot (20\,in)^{3}$

$V = 33510.322\,in^{3}$

b) The surface area of the sphere is:

$A_{s} = 4\pi \cdot (20\,in)^{2}$

$A_{s} = 5026.548\,in^{2}$

c) The total differentials for volume and surface area of the sphere are, respectively:

$\Delta V = 4\pi\cdot r^{2}\,\Delta r$

$\Delta V = 4\pi \cdot (20\,in)^{2}\cdot (0.03\,in)$

$\Delta V = 150.796\,in^{3}$

$\Delta A_{s} = 8\pi\cdot r \,\Delta r$

$\Delta A_{s} = 8\pi \cdot (20\,in)\cdot (0.03\,in)$

$\Delta A_{s} = 15.080\,in^{2}$

Relative errors are presented hereafter:

$\%V = \frac{\Delta V}{V}\times 100\%$

$\%V = \frac{150.796 \,in^{3}}{33510.322\,in^{3}}\times 100\,\%$

$\% V = 0.450\,\%$

$\% A_{s} = \frac{\Delta A_{s}}{A_{s}}\times 100\,\%$

$\% A_{s} = \frac{15.080\,in^{2}}{5026.548\,in^{2}}\times 100\,\%$

$\%A_{s} = 0.300\,\%$

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3 years ago

What is the value of 9a + 6b?

Svetlanka [38]

i) 3a+2b=9 /*3

9a+6b=27

ii) 8x+6y=60 /: 2

4x+3y=30

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A trapezoid has an area of 30 in2. If the lenghts of the bases are 4.8 and 5.2 in, what is the lenght?

harkovskaia [24]

Looking for the height, if trapezoid area equals (a+b)/2 x h then h = 2A/(a+b)
so h = 2(30)/(4.8+5.2) = 6

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3 years ago