A chemist has 200 mL of a 10% sucrose solution. She adds x mL of a 40% sucrose solution. The percent concentration, y, of the fi

Question

4 years ago

13

A chemist has 200 mL of a 10% sucrose solution. She adds x mL of a 40% sucrose solution. The percent concentration, y, of the fi

nal mixture is given by the rational function:
The chemist needs the concentration of the final mixture to be 30%. How many milliliters of the 40% solution should she add to the 10% solution to get this concentration?

Mathematics

2 answers:

Degger [83] · Answer 1 · 2021-12-10T07:35:56+03:00

Degger [83]4 years ago

5 0

Answer:

0.1(200)+ 0.4x

Step-by-step explanation:

the next couple ones are

200+x

and

C

sattari [20] · Answer 2 · 2021-12-10T06:34:36+03:00

Answer:

We need to add 400 ml of the 40% solution

Step-by-step explanation:

We take the amount times the percent concentration and add what we mix to get the final concentration

We need the final mixture to be 30% and we have 200 +x milliliter added together so that will be the amount in the container

200 * 10 % + x* 40 % = (200+x) *30%

Change the percent to decimal form

200 * .10 + x* .40 = (200+x) *.30

Distribute the .30

20 + .4x = 60+.3x

Subtract .3x from each side

20 + .4x-.3x = 60+.3x-.3x

20 +.1x = 60

Subtract 20 from each side

20-20 +.1x = 60-20

.1x = 40

Divide by .1

.1x/.1 = 40/.1

x=400

We need to add 400 ml of the 40% solution