Answer:
angle CBE=15 degrees
Step-by-step explanation:
angle ECD is 60 degrees and EC=CD because equilateral triangle
angle DCB is 90 degrees and CB=CD because square
angle ECD +angle DCB= angle ECB
60+90=150=angle ECB
since triangle ECB has legs EC and CB equal in length, then it is an isosceles triangle.
so angles CBB and CBE are equal
angle CBE=(180-150)/2
angle CBE=15 degrees
Answer:
<h3>80 feet</h3>
Step-by-step explanation:
Given the path of a projectile launched from a 16-ft-tall tower modeled by the equation y = −16t^2 + 64t +16
h is the maximum height reached
t is in seconds
The velocity of the projectile at its maximum height is zero;
velocity v = dy/dt
v = -32t + 64
Since v = 0 at maximum height
0 = -32t + 64
32t = 64
t = 2secs
Substitute t = 2secs into the equation of the height to get the maximum height.
y = −16t^2 + 64t +16
at t = 2secs
y = −16(2)^2 + 64(2) +16
y = -64 + 128 + 16
y = 64+16
y = 80 feet
Hence the maximum height, in feet, reached by the projectile is 80 feet
72.5 weeks. if you subtract 1,000 from 2,450, you will have 1,450. now, divide this by 20. it is 72.5 weeks.
When two linear equations have only one solution the two lines on a graph would intersect each other ( they would only touch in one spot).
