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Lena [83]
2 years ago
13

Write "48 gallons in 14 days" as a unit rate. Round to the nearest hundredth, if necessary.

Mathematics
1 answer:
devlian [24]2 years ago
6 0
(48 gallons) / (14 days) = 3.428571429 gallons/day = 3.43 gallons/day

Answer: 3.43 gallons/day
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The distance from Jason’s house to school is 0.5 kilometer. What is this distance in meters?
Leno4ka [110]

Answer:

500

Step-by-step explanation:

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2 years ago
HELPPPP Write the equation of a line in slope intercept form with a slope of -3/4 and a y-intercept of -9.
Vanyuwa [196]

Answer:

y=-3/4x-9

Step-by-step explanation:

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5 0
3 years ago
Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
2 years ago
Find the greatest common factor 32a^3b^2, 44ab^3 and 40a^2b
Ronch [10]
\32a^3b^2 \ , \  44ab^3 \ , \  40a^2b\\&#10;

\text {Taking out common factor : } \\ \\&#10;4ab(8a^2b) + 4ab(11b^2) + 4ab(10a)

\text { greatest common factor =  } 4ab
3 0
3 years ago
An angle measure is 72.3 degrees. What is the measure of its complement? (I already tried 17.7 and that’s not correct).
Makovka662 [10]

Answer:

I got 17.7°

Step-by-step explanation:

Since a complimentary angle adds up to 90 degrees, this would be the right answer... does it require a degree symbol?

6 0
3 years ago
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