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Andrew [12]
3 years ago
5

A couple of students are testing a prototype for a science project on rockets. They launch the rocket and record its height over

time. The table shows the height of the rocket in meters, f(x), and the time in seconds after launch, x. Create the function, in standard form, that models this situation.

Mathematics
2 answers:
Illusion [34]3 years ago
8 0
For this case we have the following table:
 x    f(x)
 <span><span><span>0     2
 </span><span>1     5
 </span><span>2    10
 </span><span>3     17
</span></span></span> The equation that best fits the data in the table, for this case, is given by a quadratic function.
<span><span><span> </span></span></span>The quadratic function in its standard form is:
 f (x) = x2 + 2x + 2
 Answer:
 f (x) = x2 + 2x + 2
Gnoma [55]3 years ago
8 0

Answer:

Substitute b = 2 in the equation 3 = a + b and solve to get a = 1.

Substitute the values of a = 1, b = 2, and c = 2 in the standard form of the quadratic function:

<u>f(x) = x^2 + 2x + 2</u>

<u><em>This is the right answer for Edmentum and Plato users. </em></u>

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aivan3 [116]

Answer:

Step-by-step explanation:

Its like doing a long division with base 10 numbers:

           1110    <----------- Quotient

101)1001010

        101

         1000

            101

               111

                101

                  100

So the answer is 1110 remainder 100.

We can confirm this by converting to decimal numbers

1001010 = 74 and 101 = 5.

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3 0
2 years ago
What property is -6+24=x-24+24
Ipatiy [6.2K]

Answer:

x = 30

Step-by-step explanation:

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x = 30 - 0

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2 years ago
Figure 1 is dilated to get Figure 2.
Anastasy [175]
Answer: 2.25

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3 0
2 years ago
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valina [46]

Answer:

\displaystyle T'(  2,4)

\displaystyle U'( 1,1)

\displaystyle S' ( 3,2)

Step-by-step explanation:

we current vertices of the given triangle

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  • \displaystyle U( - 1,1)
  • \displaystyle S ( - 3,2)

remember that,

\rm\displaystyle(x,y) \xrightarrow{ \rm reflection \:  over \: y - axis}( -  x,y)

so we obtain:

\rm\displaystyle \: T( - 2,4) \xrightarrow{ \rm reflection \:  over \: y - axis}T'(  2,4)

\rm\displaystyle \: U( - 1,1) \xrightarrow{ \rm reflection \:  over \: y - axis}U' ( 1,1)

\rm\displaystyle S( - 3,2) \xrightarrow{ \rm reflection \:  over \: y - axis}S'( 3,2)

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Answer:

A

Step-by-step explanation:

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