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NemiM [27]
3 years ago
7

-a^2b^2c^2(a+b-c) find the product

Mathematics
1 answer:
irakobra [83]3 years ago
5 0

Answer:

-a^3b^2c^2-a^2b^3c^2+a^2b^2c^3

I hope it will be useful.

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Can someone help me with this? he didn't lecture on finding points other than when t=0, so i am very, very lost. thanks. don't k
NARA [144]
Firstly, we  must calculate dx/dt , 
dx/dt = 4te^t + 4e^t=(<span>4t + 4)e^t
</span>dx/dt=0 implies (4t + 4)e^t=0 so 4t + 4 = 0 because <span>e^t>0, and t= -1,
</span>fort t = -1, x = 4 (-1)e^-1, and <span>y=4(-1)e^1,
x= - 4 / e, and </span><span>y= - 4 e
</span><span>Then find the exact coordinates. 
Highest point:- 4/e
Leftmost point:   - 4e
</span><span>Horizontal asymptote: lim </span><span>4te^_t
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t=infinity      t=infinity
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t= - infinity  t= - <span>infinity
</span>
<span>The curve has one horizontal asymptote and one vertical asymptote. Find them. 
Horizontal asymptote: y= . 0
Vertical asymptote: x= 0</span>
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