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storchak [24]
3 years ago
12

Last question I need done for my assignment!!! Help would be greatlyyyy appreciated!

Mathematics
1 answer:
sergejj [24]3 years ago
7 0

Answer: 22\ units^2

Step-by-step explanation:

You need to remember that the area of a rectangle can be found using this formula:

A=lw

Where "A" is the area of the rectangle, "l" is the length and "w" is the width.

As you can observe in the picture attached, you can divide the figure into four rectangles (identified as A,B,C and D) whose dimensions are also shown in the picture.

Then, applying the formula, you get that the area of each rectangle is:

A_A=l_Aw_A=(6\ units)(1\ unit)=6\ units^2\\\\A_B=l_Bw_B=(4\ units)(2\ units)=8\ units^2\\\\A_C=l_Cw_C=(3\ units)(2\ units)=6\ units^2\\\\A_D=l_Dw_D=(2\ units)(1\ unit)=2\ units^2

Therefore, you need to add the areas of the rectangles calculated before in order to find the area of the figure.

You get that this is:

A_f=6\ units^2+8\ units^2+6\ units^2+2\ units^2\\\\A_f=22\ units^2

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Step-by-step explanation:

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3 years ago
Help please 50 points!​
uranmaximum [27]

Answer:

A and B

Step-by-step explanation:

we would like to solve the following equation:

\rm\displaystyle 5 - 2x =  \sqrt{ {2x}^{2} + x - 1 }  - x

to do so isolate -x to the left hand side and change its sign:

\rm\displaystyle 5 - 2x + x =  \sqrt{ {2x}^{2} + x - 1 }

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\rm\displaystyle (5 - x {)}^{2}  =  (\sqrt{ {2x}^{2} + x - 1 }  {)}^{2}

simplify square of the right hand side:

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use (a-b)²=a²-2ab+b² to expand the left hand side:

\rm\displaystyle  {x}^{2}  - 10x + 25=  {2x}^{2} + x - 1

swap the equation:

\rm\displaystyle   {2x}^{2} + x - 1 =  {x}^{2}  - 10x + 25

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by <em>Zero</em><em> </em><em>product</em><em> </em><em>property</em> we obtain:

\displaystyle    \begin{cases}x- 2  = 0\\ x   +  13=  0 \end{cases}

solve for x:

\displaystyle    \begin{cases}x = 2\\ x  =   - 13 \end{cases}

to check for extraneous solutions we can define the domain of equation recall that a square root of a function is always greater than or equal to 0 therefore

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solve the inequality for x:

\rm\displaystyle x    \leqslant  5

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