Answer:
William will make 12 bags of food and each of the bag will contains 2 cans of fruit and 5 cans of vegetables.
Step-by-step explanation:
Given:
Number of fruits cans = 24
Number of veggies cans = 60
William will have to distribute them in equal bags with equal cans of fruits and vegetables respectively.
For this:
We have to find the GCF (greatest common factor) of 24 and 60.
GCF by listing out the factors method.
Factors of 24 :
Factors of 60 : 
So,
The greatest common factor of
and
is
.
The number of bags William will used for equal distribution = 
Now,
We have to distribute the veggies and fruits in equal number of cans to these
bags.
Number of fruits cans used in each bag =
Number of vegetables can used in each bag = 
We can say that:
William will make 12 bags of food and each of the bag will contains 2 cans of fruit and 5 cans of vegetables.
We set up a proportion: 84/?= 56/100
Cross multiply: 56*?= 84*100
⇒ ?= 84*100/56= 150
56% of 150 is 84.
Is A & C.
Explanation:
A. Median for sea turtles:
The set is odd, so median is the middle number - 4
The koi set had 10, even number, so the median for the koi is the average of the 2 middle: 4+3=3.5
Turtles > koi
C. The ages of koi are more spread out - 10. The turtles are only 5.
Answer:
this is what I got
Step-by-step explanation: