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Sergeu [11.5K]
3 years ago
6

A triangle has one side of length 29 units and another of length 40 units. Determine the range in which the length of the third

side must lie.
A. -11< x < 69

B. 11≤ x ≤ 69

C. 11< x < 69

D. -11≤ x ≤ 69
Mathematics
1 answer:
Vlada [557]3 years ago
4 0

Answer:

C

Step-by-step explanation:

The triangle inequality theorem tells us that if two sides of a triangle are known (let it be side a and b), we can know the length of range of third side (side c). By:

a-b< c < a+b

So sides are given 29 and 40.

Sum is 29 + 40 = 69

Difference is 40 - 29 = 11

Hence, the third side would be BETWEEN 11 and 69

C is the correct choice.

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Homework: HW 2: Sections 5.2-5.4
pickupchik [31]

Answer:

Group

AB

- 51 12

- 14

5

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Rh

Step-by-step explanation:

8 0
3 years ago
Not sure how to simplify this? Help please!
Crazy boy [7]
So lets start by getting rid of the fraction. In order to do this we must move the 'u' to the other side by multiplying it. 

8*u =  -\frac{4}{u}*u

8u = -4

Now we need to isolate the 'u' so we must bring the 8 over to the other side by dividing both sides by 8. 

\frac{8u}{8} = \frac{-4}{8}

u =  \frac{-4}{8}

Therefore:
u = - \frac{1}{2} = -0.5

Hope this helps!
8 0
3 years ago
MULTIPLE CHOICE
cricket20 [7]
Add the equations together so that you get 6x=-4, how I got their is cancel out the +/-3 and then add the -10+6=-4. Then you’d bring over the 6 and it would look like this x=-4/6 which you would simplify by dividing 2 into the 4 and 6 and should look like this x=-2/3
3 0
4 years ago
ACELLUS HELP ASAP
inessss [21]
22% (22/100=.22=22%) if you look at the graph, the question aks what is the percentage of a person getting a hot drink that is a large... you find that section and collect the total which is 100 then follow what i did in the beginning
6 0
3 years ago
Meg is a veterinarian. In a given week, 50% of
krek1111 [17]

Answer:

<u><em></em></u>

  • <u><em>a. Meg needs to find the part</em></u>

<u><em></em></u>

  • <u><em>b. Steve needs to find the percent.</em></u>

<u><em></em></u>

Step-by-step explanation:

The question is incomplete.

This is the complete question:

<em>Meg is a veterinarian. In a given week, 50% of the 16 dogs she saw were Boxers. Steve is also a veterinarian. In the same week, 7 of the 35 dogs he saw this week were Boxers. Each wants to record the part the whole, and the percent.</em>

<em />

<em>a. Does Meg need to find the part, the whole, or the percent.</em>

<em />

<em>b. Does Steve need to find the part, the whole, or the percent.</em>

<em />

<h2>Solution to the problem</h2>

<u><em>a. Does Meg need to find the part, the whole, or the percent.</em></u>

<em />

<em>Meg</em> already knows the <em>whole</em> and the <em>percent</em>.

The whole is the entire number of dogs seen: <em>16 dog</em>s.

The percent is <em>50%.</em>

Hence, she needs to find the part: this is how many (what part) of the 16 dogs she saw were boxers.

And she can do with a simple operation:

  • Part = whole × percent = 16 × 50% = 8. This is 8 dogs of 16 were boxers.

<u>b. Does Steve need to find the part, the whole, or the percent.</u>

<u></u>

He already knows <em>the part</em> (<em>7 of the 35 dogs were boxers</em>) and <em>the whole </em>(<em>35 dogs</em>).

Then he needs to find the percent, which he can do using the next operation:

  • Percent = (part / whole) × 100 = (7/35)×100 = 20%
6 0
4 years ago
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