What are the similarities between a factor and multiple

Which line is perpendicular to a line that has a slope of 1/2?

Flura [38]

Answer:

HJ

Step-by-step explanation:

For a line to be perpendicular to another line, you must find the negative reciprocal.

The negative reciprocal of 1/2 is -2.

The only line with a slope of -2 is line HJ because it goes down 2 for every 1 to the right.

8 0

3 years ago

The failure of a circuit board interrupts work that utilizes a computing system until a new board is delivered. The delivery tim

Hatshy [7]

Answer:

The expected cost is 152

Step-by-step explanation:

Recall that since Y is uniformly distributed over the interval [1,5] we have the following probability density function for Y

$f_Y(y ) = \frac{1}{5-1} = \frac{1}{4}$ if $1\leq y \leq 5$ and 0 othewise. (To check this is the pdf, check the definition of an uniform random variable)

Recall that, by definition

$E(Y^k) = \int_{-\infty}^{\infty} y^kf_Y(y)dy$

Also, we are given that $C = 50+3Y+9Y^2$ . Recall the following properties of the expected value. If X,Y are random variables, then

$E(a+bX+cY) = a+bE(X)+cE(Y)$

Then, using this property we have that $E[C] = 50+3E[Y]+ 9E[Y^2]$ .

Thus, we must calculate E[Y] and E[Y^2].

Using the definition, we get that

$E[Y] = \int_{1}^{5}\frac{y}{4} dy =\frac{1}{4}\left\frac{y^2}{2}\right|_{1}^{5} = \frac{25}{8}-\frac{1}{8} = 3$

$E[Y^2] = \int_{1}^{5}\frac{y^2}{4} dy =\frac{1}{4}\left\frac{y^3}{3}\right|_{1}^{5} = \frac{125}{12}-\frac{1}{12} = \frac{31}{3}$

Then

$E(C) = 50 + 3\cdot 3 + 9 \cdot \frac{31}{3} = 152$

5 0

3 years ago

A mass oscillating up and down on the bottom of a spring (assuming perfect elasticity and no friction or air resistance) can be

alexdok [17]

The motion of the mass as it moves on the bottom of the spring is a

repetitive motion.

$\mathrm{The \ motion \ of \ the \ mass \ attached \ to \ the \ spring \ is \ }\displaystyle d = 6 \cdot sin\left(\frac{\pi}{2} \cdot t \right)$

Reasons:

The general form of the equation of the simple harmonic motion of the

mass is <em>d</em> = a·sin(ω·t)

Where;

d = The distance of the mass from the rest position

a = The maximum displacement of the mass from the equilibrium position = 6 cm

ω = The frequency of rotation

t = The time of motion

ω = The frequency of rotation

$\displaystyle \omega = \mathbf{\frac{2 \cdot \pi}{T}}$

Where;

T = The time to complete one cycle (the period of oscillation) = 4 seconds

$\displaystyle \omega = \frac{2 \cdot \pi}{4} = \frac{\pi}{2}$

Combining the above values gives the modelling equation as follows;

$\displaystyle d = 6 \cdot sin\left(\frac{\pi}{2} \cdot t \right)$

Learn more here:

brainly.com/question/12904891

3 0

2 years ago

Which answers show y + 2x < 4x - 3, rewritten to isolate y, and it’s graph?

AnnyKZ [126]

Solving y+2x < 4x-3 for y would lead to y < 2x-3. You subtract 2x from both sides of the original inequality to get to this result.

To graph y < 2x-3, you first graph y = 2x-3 which is a straight line that goes through (0,-3) and (1,-1). This line is a dashed or dotted line as solutions are not found on the boundary. The shaded region is below the dashed/dotted boundary line to indicate where the solution set is.

To summarize: the graph is a dashed line through (0,-3) and (1,-1) with the shading below the dashed line

The answer is between A and B. It will depend on how those graphs look as to which is the final answer.

6 0

3 years ago

Read 2 more answers

Katie cut out a piece of wrapping paper that was 2 times as long and 3times as wide as the box that she was wrapping.The box was

mihalych1998 [28]

10+10+12+12
44 inches

5 0

4 years ago

Read 2 more answers