Whats the rest of the quiestion
<h2><u>hope</u><u> it</u><u> helps</u></h2>
<u>kindly</u><u> </u><u>see </u><u>the</u><u> attachment</u>
Let
x-------> the length of the base of triangle
y-------> the height of the triangle
we know that
the area of the triangle is equal to
in this problem we have
so
--------> equation 
--------> equation 
Substitute equation in equation
![\frac{1}{2}x[2x+4]\leq 168](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dx%5B2x%2B4%5D%5Cleq%20168)
therefore
<u>the answer is</u>
The inequality that can be used to find the possible lengths, x, of the base of the triangle is or
<h3>
Answer: Choice B</h3><h3>
sqrt(3)/2, 1/2, sqrt(3)</h3>
================================================
Explanation:
Sine of an angle is the ratio of the opposite side over the hypotenuse. For reference angle A, the opposite side is BC = 6sqrt(3). The hypotenuse is the longest side AB = 12
Sin(angle) = opposite/hypotenuse
sin(A) = BC/AB
sin(A) = 6sqrt(3)/12
sin(A) = sqrt(3)/2
---------------
Cosine is the ratio of the adjacent and hypotenuse
cos(angle) = adjacent/hypotenuse
cos(A) = AC/AB
cos(A) = 6/12
cos(A) = 1/2
---------------
Tangent is the ratio of the opposite and adjacent
tan(angle) = opposite/adjacent
tan(A) = BC/AC
tan(A) = 6sqrt(3)/6
tan(A) = sqrt(3)
Sorry can't help you with that...wish I could
