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V125BC [204]
3 years ago
6

Ln a+3 + ln a-3 = ln 16

Mathematics
1 answer:
Lilit [14]3 years ago
7 0
\bf log_{{  a}}(xy)\implies log_{{  a}}(x)+log_{{  a}}(y)\\\\
and\qquad \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
ln(a+3)+ln(a-3)=ln(16)\implies ln[(a+3)(a-3)]=ln(16)
\\\\\\
ln[a^2-3^2]=ln(16)\impliedby \textit{removing ln() from both sides}
\\\\\\
a^2-9=16\implies a^2=16+9\implies a^2=25
\\\\\\
a=\pm\sqrt{25}\implies a=\pm 5
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What is the solution: <br><br> 256x + 2 = 43x + 9
ruslelena [56]

<u>Answer:</u>

x = \bf \frac{7}{213}

<u>Step-by-step explanation:</u>

To find the solution to the equation, we have to rearrange the equation to make x the subject:

256x + 2 = 43x + 9

⇒ 256x + 2 - 2 = 43x + 9 - 2             [Subtracting 2 from both sides]

⇒ 256x = 43x + 7

⇒ 256x - 43x = 43x + 7 - 43x           [Subtracting 43x from each side]

⇒ 213x = 7

⇒ \frac{213}{213}x = \frac{7}{213}                                       [Diving both sides by 213]

⇒ x = \bf \frac{7}{213}

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