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2 answers:
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Answer:
See below
Step-by-step explanation:
I assume the function is
A) The vertical asymptotes are located where the denominator is equal to 0. Therefore, is the only vertical asymptote.
B) Set the first derivative equal to 0 and solve:
Now we test where the function is increasing and decreasing on each side. I will use 2 and 1 to test this:
Therefore, the function increases on the interval and decreases on the interval
.
C) Since we determined that the slope is 0 when from the first derivative, plugging it into the original function tells us where the extrema are. Therefore,
, meaning there's an extreme at the point
, but is it a maximum or minimum? To answer that, we will plug in
into the second derivative which is
. If
, then it's a minimum. If
, then it's a maximum. If
, the test fails. So,
, which means
is a local maximum.
D) Now set the second derivative equal to 0 and solve:
We then test where is negative or positive by plugging in test values. I will use -1 and 3 to test this:
, so the function is concave down on the interval
, so the function is concave up on the interval
The inflection point is where concavity changes, which can be determined by plugging in into the original function, which would be
, or
.
E) See attached graph
there are 4 of the 10-nf and 8 of the 100-nf capacitors which is a total of 12 items.
the probability of drawing a 10-nf is: 4 out of 12 =
the probability of drawing a 100-nf is: 8 out of 12 =
(a) "at least two" means: 2 or 3 or 4
Probability of 2 (10's) and 2 (100's): x
x
x
=
Probability of 3 (10's) and 1 (100's): x
x
x
=
Probability of 4 (10's) and 0 (100's): x
x
x
=
2 or 3 or 4: +
+
=
(b) without replacement
Probability of 2 (10's) and 2 (100's): x
x
x
=
Probability of 3 (10's) and 1 (100's): x
x
x
=
Probability of 4 (10's) and 0 (100's): x
x
x
=
2 or 3 or 4: +
+
=
=
=