All categories

2 years ago

The equation y²/8² - x²/b² represents a hyperbola centered at the origin with a focus of (0, -10).

Mathematics

2 answers:

cestrela7 [59]2 years ago

6 0

Answer:

b = 6

Step-by-step explanation:

You probably already know the general equation from the my last couple of answer.

In this question, we have:

a=8

b= ?

c= -10 , c is the value of the foci

surprisingly, you can solve the value for a, b, and c using the same equation as the Pythagorean theorem.

c² = a² + b²

we need to solve for b so lets rearrange the equation.

b² = c² - a²

b = ±√(c² - a²)

b = ±√((-10)² - (8)²)

b = ±√(100 - 64)

b = ±√(36)

b = ±6

b = 6

blsea [12.9K]2 years ago

6 0

Answer: 6

Step-by-step explanation:

You might be interested in

NOWW WILL GIVE BRAINLIEST

Firlakuza [10]

Answer:

No 4,800

Step-by-step explanation:

8 0

2 years ago

Please help!! 30 pts! thanks!

mel-nik [20]

Answer:

Eu não sei cara, sinto muito, cara, não me denuncie ou você é apenas um idiota metido

Step-by-step explanation:

Eu não sei cara, sinto muito, cara, não me denuncie ou você é apenas um idiota metido

5 0

2 years ago

Read 2 more answers

Felicia is building a rectangular garden. The garden will have a perimeter of 20 meters. Give three pairs of possible side lengt

Lynna [10]

8 and 2: 8+8+2+2
7 and 3: 7+7+3+3
6 and 4: 6+6+4+4
=20

5 0

2 years ago

Select the correct answer. For what value of x is sin x = cos 19º, where 0°< x < 90°? OA. 38° ° O B. 71° OC. 26° O D. 19°

Lerok [7]

Answer:

x = 71°

Option B is correct answer.

Step-by-step explanation:

We need to find for what value of x is $sin\: x = cos 19^{\circ}$ , where 0°< x < 90°?

Solving:

$sin\: x = cos\: 19^{\circ}\\Finding \:cos\: 19^{\circ}=0.94551\\Putting\:value:\\sin\:x=0.94551\\Now\:taking\:sin\:inverse\\x=sin^{-1}(0.94551)\\x=71^{\circ}$

So, we get x = 71°

Option B is correct answer.

5 0

2 years ago

Can someone help me ASP.

Ivahew [28]

Answer:

The anwsers are

a- trapezoid

b- 6

8 0

3 years ago

Read 2 more answers