The equation y²/8² - x²/b² represents a hyperbola centered at the origin with a focus of (0, -10).
2 answers:
You might be interested in
Answer:
The measure of the arc PJ is
Step-by-step explanation:
step 1
Find the measure of angle L
we know that
In a inscribed quadrilateral opposite angles are supplementary
so
we have
substitute
step 2
Find the measure of arc KJ
we know that
The inscribed angle measures half that of the arc comprising
so
substitute the values
step 3
Find the measure of arc PJ
we know that
The inscribed angle measures half that of the arc comprising
so
substitute the values
Step-by-step explanation:
We have been given an equation y+6=45(x+3) in point slope form.
It says to use the point and slope from given equation to create the graph.
So compare equation y+6=45(x+3) with point slope formula
y-y1=m(x-x1)
we see that m=45, x1=-3 and y1=-6
Hence first point is at (-3,-6)
slope m=45 is positive so to find another point, previous point will move 45 units up then 1 unit right and reach at the location (-2,39).
Now we just graph both points (-3,-6) and (-2,39) and join them by a straight line. Final graph will look like the attached graph.
