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inn [45]
3 years ago
13

Which expression represents the greatest common factor (GCF) of 30 and 80? A. 2 X 5 B. 2 X 7 C. 7 X 5 D. 2 X 2 X 5

Mathematics
2 answers:
inessss [21]3 years ago
6 0

30 = 5*6  = 5 * 3*2

80 = 8* 10 = 2*2*2 * 2 *5

The CGF is the numbers that appear in both  

2 appears 1 time in both and 5 appears 1 time in both

GCF 2*5

Choice A

Archy [21]3 years ago
6 0

So, you first need to find the GCF of 30 and 80.

80 - 1,2,4,5,8,10,16,20,40,80

30 - 1,2,3,5,6,10,15,30

Find the highest number that can go with both of these numbers.

The highest factor that can multiply to both of these numbers is 10.

Now, find the answer that has the right multiples to 10.

10 - 1,2,5,10.

The only answer with the right multiples matching up with the factors is         A. 2 × 5

So, your answer is <em>A. 2 × 5</em>

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Savatey [412]

answer : 2 1/2

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divide  2 1/2 by 1

its 2 1/2

10 divided by 4 is also

2 1/2

17 1/2 divided by 7 is also

2 1/2

6 0
2 years ago
Worksheet Check
Maurinko [17]
Hey i think the only mistake i caught was when you put 3 points under the line mark instead of only needing 2.
Possibly another mistake at 3a, Only 2 points (but i could be wrong)

6 0
3 years ago
Sravya earns $42,820 per year in take home pay. What is the most money a housing expert would advise her to spend on a monthly m
Margarita [4]

Answer:

Step-by-step explanation:

the most money a housing expert would advise her to spend on a monthly mortgage payment would be 1,645

3 0
2 years ago
The Scottsdale fire department aims to respond to fire calls in 4 minutes or less, on average. Response times are normally distr
IgorC [24]
<h2><u>Answer with explanation</u>:</h2>

Let \mu be the population mean.

As per given , we have

H_0:\mu \leq4\\\\ H_a: \mu >4

Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.

Also, population standard deviation is given \sigma=1 , so we perform one-tailed z-test.

Test statistic : z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

, where \mu = Population mean

\sigma = Population standard deviation

n= sample size

\overline{x} = Sample mean

For n= 18 , \overline{x}=4.50 , \sigma=1 , \mu =4, we have

z=\dfrac{4.5-4}{\dfrac{1}{\sqrt{18}}}\approx2.12

P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12)  [∵ P(Z>z)=1-P(Z≤z)]\

=1- 0.0340=0.9660

Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.

[We reject null hypothesis if p-value is larger than the significance level . ]

Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .

3 0
3 years ago
The graph shows the functions f(x), p(x), and g(x):
Zinaida [17]
A) The solutions to this set of equation is where the graphs cross. They cross at point (-3, -2).

B) The solutions for f(x) would be points that fall on the graph of f(x). Two possible points are (-3, -2) and (-7, 3)

C) These 2 functions cross at (4, 1). That is the solution.
3 0
3 years ago
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