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ratelena [41]
2 years ago
9

2y⁴-18x²y²-48xy²-32y²​

Mathematics
1 answer:
Goryan [66]2 years ago
6 0

Answer:

mk

Step-by-step explanation:

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Henry plans to buy Pepsee for people to drink at his birthday party. The grocery store has a sale
Ksenya-84 [330]

Answer:4,67

Step-by-step explanation:

4 0
3 years ago
Work out the value of (6.8 x 10²) x (1.3 x 10°)<br>Give your answer in standard form.​
bearhunter [10]

Hey there!

Answer: \boxed{8840}

Explanation:

(6.8*10^2)*(1.3*10)

Let's simplify.

\boxed{8840} \text{ is your answer.}

Hope this helps!

\text{-TestedHyperr}

6 0
2 years ago
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Which direction would the graph of y=3|x|-8 open
ss7ja [257]
The graph would open at the down at the bottom
8 0
3 years ago
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Find the are of a parallelogram that has a base of 7 1/2 and a height of 5 2/7
Amiraneli [1.4K]
Use the formula for the area of a parallelogram:

\sf A=bh

Plug in what we know:

\sf A=(7\dfrac{1}{2})(5\dfrac{2}{7})

Convert both of them into improper fractions. We do this by multiplying the denominator to the whole number, adding it to the numerator, which becomes our new numerator, and we keep the denominator the same:

\sf A=(\dfrac{15}{2})(\dfrac{37}{7})

Now multiply the numerators and denominators together:

\sf A=\dfrac{15}{2}\cdot\dfrac{37}{7}\rightarrow\dfrac{15\cdot 37}{2\cdot 7}\rightarrow\dfrac{555}{14}

Convert it back into a mixed number. 14 goes into 555 thirty-nine times. 14 * 39 = 546. 555 - 546 = 9. So we have 39 wholes and 9 left over, or:

\sf 39\dfrac{9}{14}

So this is the area of the parallelogram.
6 0
2 years ago
the coordinates of the vertices of a rectangle in order are (5,2), (-1,4), (-2,1) and (4,-1). what is the perimeter of the recta
Anna [14]

Answer:

19 units

Step-by-step explanation:

Plot points  A(5,2), B(-1,4), C(-2,1) and D(4,-1) on the coordinate plane. Find lengths of all sides as distances between two points:

AB=\sqrt{(-1-5)^2+(4-2)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\BC=\sqrt{(-2-(-1))^2+(1-4)^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units\\ \\CD=\sqrt{(4-(-2))^2+(-1-1)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\DA=\sqrt{(5-4)^2+(2-(-1))^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units

The perimeter of the rectangle ABCD is

AB+BC+CD+DA=2\sqrt{10}+\sqrt{10}+2\sqrt{10}+\sqrt{10}=6\sqrt{10}\approx 18.97\ units\approx 19\ units

3 0
3 years ago
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