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Andrews [41]
3 years ago
9

Ophia earned $2,000 last month. She used 35 of her earnings to pay her bills. With the remaining money, she bought two shirts fo

r $19.99 each and a pair of earrings for $12.99. ​How much money does Sophia have left from last month's earnings? Show your work. Enter your answer and work in the box provided.
Mathematics
1 answer:
Andrej [43]3 years ago
5 0

Sophia has $ 1912.03 left from last month's earnings

<u>Solution:</u>

Given, sophia earned $2,000 last month.  

She used 35 of her earnings to pay her bills.  

With the remaining money, she bought two shirts for $19.99 each and a pair of earrings for $12.99.  

We have to find how much money does Sophia have left from last month's earnings

Now, we know that,  

<em>Left money = earned money – used money</em>

= 2000 – (bills paid + 2 shirts cost + 1 pair of ear rings)

= 2000 – (35 + 2 x 19.99 + 12.99)

= 2000 – (35 + 39.98 + 12.99)

= 2000 – (87.97) = 1912.03

Hence, Sophia has $ 1912.03 left with her.

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Seven pieces of rope have an average (arithmetic mean) length of 68 centimeters and a median length of 84 centimeters. If the le
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Answer:

The maximum possible length, in centimeters, of the longest piece of rope is 134 cm

Step-by-step explanation:

Let the seven pieces be a,b,c,d,e,f,g

Average of 7 pieces of ropes  =68

Average = \frac{\text{Sum of all lengths}}{\text{No. of pieces}}

68= \frac{\text{Sum of all lengths}}{7}

68 \times 7 =\text{a+b+c+d+e+f+g}

476=\text{a+b+c+d+e+f+g} --A

We are given that the median length of a piece of rope is 84 centimeters.

We arrange the pieces in the ascending order

So, median will be the length of 4th piece

So, d = 84 cm

the length of piece a,b,c will be less than 84 and the value of e,f,g must be greater than or equal to 84

Let us suppose the length of a,b,c be x

Let us suppose the length of e,f be 84

The length of the longest piece of rope is 14 centimeters more than 4 times the length of the shortest piece of rope

So, g = 4x+14

Substitute the value in A

476=x+x+x+84+84+84+4x+14

476=7x+266

\frac{476-266}{7}=x

30=x

g = 4x+14=4(30)+14=134

Hence the maximum possible length, in centimeters, of the longest piece of rope is 134 cm

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