It would be zero because you can’t raise 0 to any positive power.
Wow that is super easy dude look on the internet
Recall that
sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1
for all <em>θ</em>, and given that cos(<em>θ</em>) < 0, we find that
cos(<em>θ</em>) = -√(1 - sin²(<em>θ</em>)) = -√(1 - (2/5)²) = -√(21)/5
Now,
csc(<em>θ</em>) = 1/sin(<em>θ</em>) = 1/(2/5) = 5/2
and
cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>) = (-√(21)/5)/(2/5) = -√(21)/2
Number of different bases for each one:
1 1 12 --->1 1 12, 1 12, 1 ----- 2 of them
1 2 6 ---> 1 2 6, 1 6, 2, 2 6 1 --- 3 of them
1 3 4 ---> 1 3 4, 1 4 3, 3 4 1 --- 3 of them
2 2 3 ---> 2 2 3, 2 3 2 ----- 2 of them
Answer-10 different prisms