Hey! Glad I can help!!!
0.4 is the tenth in there.
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Solution:
Given: zj = 3- j2, zz = - 4 + j3
Part a:
zj = 3- j2 = 
zz = - 4 + j3 = 
Part b:
|zj| = |3− j2| = √3² +(−2)² = √13 = 3.60
|z1| = √(3− j2)(3+ j2) = √
13 = 3.60.
Part c:
With the help of part a:
z1z2 = 
The factored expression would look like this : 3(x+8)(x-8)
Nothing to "solve" here. Just graph this absolute value function.
Note that if x=2 we get y = -4. Thus, (2,-4) is the vertex. Plot this point.
Now, starting from (2, -4), draw a line at a 45 degree angle to the horizontal.
Then draw a corresponding line on the other side of the y-axis. You're done!
