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2 years ago

According to a height and weight chart, Bruce's ideal wrestling weight is 168 pounds. Bruce

Mathematics

1 answer:

jek_recluse [69]2 years ago

5 0

Super simple

So he wants to be three pounds away from his ideal weight (168)

Which means he can either be 3 pounds under or 3 pounds over

So his min is 165, his max is 171

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This is image may be result of the...

Lerok [7]

construction of an angle bisector

of 60° into 30°and 30°

8 0

2 years ago

The positive acute angle formed by the _____ side of an angle in standard position and the x-axis is called a reference angle.

Helga [31]

Answer:

option-C

terminal

Step-by-step explanation:

We know that

reference angle is between terminal side and x-axis

so, the other side will be terminal position

so, we can write as

The positive acute angle formed by the <u>terminal</u> side of an angle in standard position and the x-axis is called a reference angle.

So,

option-C

terminal

7 0

3 years ago

An isotope of iodine has a mass of 134 amu. How many neutrons does the

Nina [5.8K]

Answer:

The correct option is C: the isotope of iodine contains 81 neutrons.

Step-by-step explanation:

The mass (A) of the iodine isotope is given by:

$A = Z + N$

Where:

Z: is the number of protons

N: is the number of neutrons

For iodine Z= 53, so if A = 134 the number of neutrons is:

$N = A - Z = 134 - 53 = 81$

Therefore, the correct option is C. The isotope of iodine contains 81 neutrons.

I hope it helps you!

5 0

2 years ago

What’s the cube root of -9

Aneli [31]

It might be -3 because 3•-3 is -9?

7 0

2 years ago

A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

7 0

3 years ago