Answer:
1.) 12000
2.) 6750
3.) 2.41
Step-by-step explanation:
Given the Equation :
f(t)=12,000(3/4)^t. ; where, t = time ; f(t) = worth of car at time, t
When, car was purchased, t = 0
t = 0
f(0) = 12000(3/4)^0
= 12000 * 1
= 12000
2.)
f(2) ; this mean the worth of the car after 2 years :
f(2)=12,000(3/4)^t.
12000(3/4)^2
12000 * 0.5625
= 6750
When car will be worth 6000
f(t) = 6000
f(t)=12,000(3/4)^t.
6000 = 12,000(3/4)^t
6000 / 12000 = (3/4)^t
1/2 = (3/4)^t
Take the log of both sides :
Log(0.5) = log(0.75)^t
log(0.5) = tlog(0.75)
- 0.301029 = - 0.124938t
t = - 0.301029 / - 0.124938
t = 2.4094
t = 2.41 years
Nice??? there is a city called nice? anyways, your answer is 5000. hope this helps :)
91
Follow the order of operations.
3^4 + 2 * 5
81 + 2 * 5 (Exponent)
81 + 10 (Multiplication)
91 (Addition)
Please consider marking this answer as Brainliest to help me advance.
Answer:
It took 2 hours longer
Step-by-step explanation:
Hey there!!
How do we solve this problem :
We will use the combinations formula to solve this :
c ( n , r ) where n = 11 and r = 2
c ( n , r ) = n ! / r ! ( n - r ) !
... 11 ! / 2 ! ( 11 - 2 ) !
... 11! / 2! × 9!
... 11! / 2 × 9!
... 11×10×9×8×7×6×5×4×3×2 / 2×9×8×7×6×5×4×3×2
... 11×10 / 2
... 11 × 5
... 55 combinations.
Hence, the required answer = 55 , option ( d )
Hope my answer helps!
